(-a^2 + 1) - (a^2 - 3) + (5a^2 - 6a^2 - 6a + 7)
(-a^2 - a^2 + 5a^2 - 6a^2) - 6a + 1 + 3 + 7
(-2a^2 - a^2) - 6a + 4 + 7
-3a^2 - 6a + 11
Answer would either both be 1500:4500 or 1500/4500
18 6/7<em /> is the awnser
Answer:
<u>Hours in first month = 8</u>
Step-by-step explanation:
AS it is given
He volunteered fr the first month = x hours
He volunteered for the second month = 12/3 times of first month
which will be = 12/3 * x
Total Hours volunteered = 40 hours
Now according to the given conditions
Volunteered first month + volunteered second month = total
putting this gives
x + 12/3 8 x = 40
as 12/3 = 4 so
it becomes
x + 4x = 40
solcing it will gives
5x = 40
x = 40/5
x = 8
<u><em>So Numbers of hours worked in first month are 8</em></u>
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<u>I hope this help you! :)</u>
