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Klio2033 [76]
3 years ago
14

How do you simplify this problem

Mathematics
2 answers:
Rudiy273 years ago
6 0
3x^-3y^2z^-1 is the simplification.
svp [43]3 years ago
6 0

\frac{6 {x}^{ - 2}  {y}^{3}  {z}^{ - 1}}{2xy}  =    \frac{2xy( 3{x}^{ - 3}  {y}^{2} {z}^{ - 1} ) }{2xy}
= 3 {x}^{ - 3}  {y}^{2}  {z}^{ - 1}
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The diagram below shows part of the graph of y=g(x) .
son4ous [18]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The related function is reflected across the x-axis and translated up 3 units. Effectively, it is reflected across the line y = 3/2. The graph of the related function is shown in blue in the attachment.

6 0
3 years ago
PLEASE IM BEGGING! HELP!
user100 [1]

Answer:

Part A: after 9 days the radius of the algae would be 12.81mm so the domain is 9. you would plot the domain at (0,9)

Part B: the y-intercept (the 9) represents the amount of algae the experiment started off with.

Part C: the rate of change is 0.

Step-by-step explanation:

4 0
3 years ago
Halp me plez I dont wanna fail ( MUST BE A EXPRESSION)
Scilla [17]

Answer:

2x+15=33

Step-by-step explanation:

Let n be the number of days he has been doing sit ups, not counting the first day. Since he does 2 more sit-ups for each day, then the number of additional sit-ups is 2n.

Since he started doing  15 sit-ups on the first day, the total number of sit-ups

after x days would be 2n+15.

Since he did a total of 33 sit ups today, then 2n+15=33

4 0
3 years ago
Evaluate the expression when m= -2.8 and n=-6.3.<br> 4n - 6m
Alex73 [517]
Answer is 42, hope this helps
5 0
3 years ago
the length of a soccer pitch is 20 m less than twice its width. the area of the pitch is 6000m^2. find its dimensions.
Setler79 [48]
X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:

x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60

x=60
2x-20=2(60)-20=120-20=100

Solution: the length is 100 m, and the width is 60 m.

To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.


8 0
3 years ago
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