The principal, real, root of:
![\sqrt[2]{55}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B55%7D)
=7.41619849
Answer:
168.75, about 169 times
Step-by-step explanation:
1 yd= 36 in
300 yd= 10800 in
10800 in/ 64 in=168.75
Can you please show me the passage?
I cant help you with anything because I need to see the passage.
Dentify<span> a </span>horizontal<span> or </span>vertical stretch<span> or </span>compression<span> of the</span>function<span> ƒ(</span>x<span>) = x2 by </span>observing<span> the </span>equation<span> of the </span>function g(x) = (9x)2<span>. ... </span>2<span>Answers. 0 votes. Let </span>f<span> (</span>x<span> ) is a </span>function<span> and c be a positive real number, the graph of the </span>function g<span> (</span>x<span> ) = </span>f<span> (c</span>x<span> ) is represented as follows. when, c > 1, the </span>function<span> .</span>
Answer: interest = $ 3,629.34
Step-by-step explanation:
Complete question
(Marlie will be starting college next year, federal unsubsidized student loan in the amount of $18,800 at 4.29%. She knows that during this non-payment time, interest will accrue at 4.29%. Suppose Marlie only paid the interest during her four years in school and the six-month grace period. What will she now pay in interest over the term of the loan.)
This question relates to interest over a single period of time and since it's not compounded, we use formula for simple interest to calculate the interest accrued.
Data;
P = $18,800
R = 4.29% = 0.0429
T = 4.5 years
S.I = ?
S.I = PRT
S.I = 18,800 * 0.0429 * 4.5
S.I = $3,629.34
Therefore she'll need to pay $3,629.34 as interest accrued.
