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blsea [12.9K]
4 years ago
15

Ann paid $5.20 in sales tax for an $80 purchase. What percent sales tax

Mathematics
1 answer:
Doss [256]4 years ago
3 0

Answer:

$22.84

Step-by-step explanation:

The tax is calculated by 0.075 * 21.25 = 1.59375 or $1.59. So the total bill is the cost of items purchased plus tax, which is $21.25 + $1.59 = $22.84.

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X² +12x+27 = 0<br><br> Find the roots of each equation by factoring
Setler79 [48]

Answer:

x = -9, -3

Step-by-step explanation:

{x }^{2} + 12x + 27 = 0

(x + 3)(x + 9) = 0

x = -3, -9

5 0
2 years ago
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Please Help me ( i give brainly) Given the graphs of the three functions below...At what x value are all functions equal to each
SIZIF [17.4K]

Answer:

7

Step-by-step explanation:

Because it is asking what X value are all the functions equal to just find a point that lies on X that they all come to.

In this case it's 7

7 0
2 years ago
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Jaden had 2 7/16 yards of ribbon. He used 1 3/8 yards of the ribbon to make a prize ribbon. How much does he have now?
klemol [59]
It would be 1 1/16 yards because you would do 2 7/16 - 3/8 and get 1 1/16
8 0
3 years ago
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A binomial experiment consists of 17 trials. The probability of success on trial 10 is 0.4. What is the probability of success o
Ivenika [448]

Answer:

.4

Step-by-step explanation:

The probability of success from each event is always equal in a binomail distribtuion because the trails are independent of each other

7 0
3 years ago
Write the linearization of the function at the points indicated. (Enter your answer as an equation. Let x be the independent var
Natalija [7]

Answer:

\displaystyle y=5+\frac{x}{10}

\displaystyle y=10+\frac{(x-75)}{20}

Step-by-step explanation:

<u>Linearization</u>

It consists of finding an approximately linear function that behaves as close as possible to the original function near a specific point.

Let y=f(x) a real function and (a,f(a)) the point near which we want to find a linear approximation of f. If f'(x) exists in x=a, then the equation for the linearization of f is

y=f(x)=f(a)+f'(a)(x-a)

Let's find the linearization for the function

y=\sqrt{25+x}

at (0,5) and (75,10)

Computing f'(x)

\displaystyle f'(x)=\frac{1}{2\sqrt{25+x}}

At x=0:

\displaystyle f'(0)=\frac{1}{2\sqrt{25+0}}=\frac{1}{10}

We find f(0)

f(0)=\sqrt{25+0}=5

Thus the linearization is

\displaystyle y=f(0)+f'(0)(x-0)=5+\frac{1}{10}x

\displaystyle y=5+\frac{x}{10}

Now at x=75:

\displaystyle f'(75)=\frac{1}{2\sqrt{25+75}}=\frac{1}{20}

We find f(75)

f(75)=\sqrt{25+75}=10

Thus the linearization is

\displaystyle y=f(75)+f'(75)(x-75)=10+\frac{1}{20}(x-75)

\displaystyle y=10+\frac{(x-75)}{20}

5 0
3 years ago
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