Answer:
16
Step-by-step explanation:
18+6=24
24-7=16
Answer:



Step-by-step explanation:
a. #We notice this is a Poisson probability function expressed as:

x-number of occurrences in a given interval.
-mean occurrences of the event
-The mean is calculated as:

#the probability of no accidents in a 15-minute period is :

Hence, the probability of no accident in a 15-min period is 
b. The the probability of at least one accident in a 15-minute period. is calculated as:

Hence, the probability of at least one accident in a 15-minute period is 
c. The probability of four or more accidents in a 15-minute period is calculated as:
![P(X\geq 4)=1-P(X\leq 3)=1-[P(X=0)+P(X1)+P(X=2)+P(X=3)]\\\\=1-[5.574\times10^{-7}+a. \ 8.026\times10^{-6}+\frac{14.4^2e^{-14.4}}{2!}+\frac{14.4^3e^{-14.4}}{3!}]\\\\=1-[8.584\times 10^{-6}+5.779\times10^{-5}+2.774\times10^{-4}]\\\\=0.9997](https://tex.z-dn.net/?f=P%28X%5Cgeq%204%29%3D1-P%28X%5Cleq%203%29%3D1-%5BP%28X%3D0%29%2BP%28X1%29%2BP%28X%3D2%29%2BP%28X%3D3%29%5D%5C%5C%5C%5C%3D1-%5B5.574%5Ctimes10%5E%7B-7%7D%2Ba.%20%5C%208.026%5Ctimes10%5E%7B-6%7D%2B%5Cfrac%7B14.4%5E2e%5E%7B-14.4%7D%7D%7B2%21%7D%2B%5Cfrac%7B14.4%5E3e%5E%7B-14.4%7D%7D%7B3%21%7D%5D%5C%5C%5C%5C%3D1-%5B8.584%5Ctimes%2010%5E%7B-6%7D%2B5.779%5Ctimes10%5E%7B-5%7D%2B2.774%5Ctimes10%5E%7B-4%7D%5D%5C%5C%5C%5C%3D0.9997)
Hence,the probability of four or more accidents in a 15-minute period. is 0.9997
Answer:
14
Step-by-step explanation:
she has 10
she gets 4 more
10+4=14
Answer:
<h2>
20</h2>
Step-by-step explanation:
Given,
X = 3
y = -2
Now,

Plugging the value of X and y

Calculate the product




Hope this helps...
Good luck on your assignment