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Fittoniya [83]
3 years ago
10

Given f(x)=1/x+3 and g(x)=6/x+4, find the domain of f(g(x))

Mathematics
1 answer:
Murljashka [212]3 years ago
4 0

Answer:

The domain is all real numbers except the value of x=-6

Step-by-step explanation:

we have

f(x)=\frac{1}{x+3}

g(x)=\frac{6}{x+4}

we know that

f(g(x))=\frac{1}{(\frac{6}{x+4})+3}

f(g(x))=\frac{1}{\frac{6+3(x+4)}{x+4}}

f(g(x))=\frac{x+4}{6+3x+12}

f(g(x))=\frac{x+4}{3x+18}

f(g(x))=\frac{x+4}{3(x+6)}

Remember that the denominator cannot be equal to zero

so

The value of x cannot be equal to -6

therefore

The domain is all real numbers except the value of x=-6

In interval notation the domain is

(-∞,-6) ∪ (-6,∞)

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Please help with this AP Calculus question !
melomori [17]

Answer:

C.  \displaystyle \frac{cos(x)}{x} - ln(x)sin(x)

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Rule [Product Rule]:                                                                             \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Trig Derivatives

Logarithmic Derivatives

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = ln(x)cos(x)

<u>Step 2: Differentiate</u>

  1. Derivative Rule [Product Rule]:                                                                     \displaystyle f'(x) = \frac{d}{dx}[ln(x)]cos(x) + ln(x)\frac{d}{dx}[cos(x)]
  2. Logarithmic Derivative:                                                                                 \displaystyle f'(x) = \frac{1}{x}cos(x) + ln(x)\frac{d}{dx}[cos(x)]
  3. Trig Derivative:                                                                                             \displaystyle f'(x) = \frac{1}{x}cos(x) + ln(x)[-sin(x)]
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Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

Book: College Calculus 10e

7 0
3 years ago
Factor the following equation to find its zeros.
Thepotemich [5.8K]

Answer:

  A|  12, 3

Step-by-step explanation:

The polynomial can be factored by looking for factors of 36 that sum to -15. The sum being negative while the product is positive means both factors will be negative. The answer choices suggest ...

  y = (x -12)(x -3)

A quick check shows this product is ...

  y = x^2 -12x -3x +36 = x^2 -15x +36 . . . . as required

The factors are zero when x is either 12 or 3.

The zeros of the equation are 12 and 3.

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Once you realize the constants in the binomial factors both have a negative sign, you can immediately choose the correct answer (A).

Or, you can use Descartes' rule of signs, which tells you that the two sign changes in the coefficients (+-+) mean there are 2 positive real roots.

6 0
3 years ago
Write the following numbers used in these statements in scientific notation. (Note: Some of these numbers have been rounded.)
lutik1710 [3]

Answer:

So in scientific form 4000 miles will be equal to 4\times 10^3miles

Step-by-step explanation:

We have given that radius of earth is 4000 miles

4000 miles can be written as 4×1000

We have to written 4000 miles in scientific form

We know that 1000 can be written in scientific form as 1000=10^3

So 4000miles =4\times 1000=4\times 10^3miles

So in scientific form 4000 miles will be equal to 4\times 10^3miles

5 0
3 years ago
NEED HELP WITH THESE QUESTIONS
amm1812

For this case we must solve the following questions:

Question 1:

We should simplify the following expression:

\frac {\frac {m ^ 2 * n ^ 3} {p ^ 3}} {\frac {mp} {n ^ 2}} =

Applying double C we have:

\frac {m ^ 2 * n ^ 3 * n ^ 2} {mp * p ^ 3} =

By definition of multiplication of powers of the same base we have to place the same base and add the exponents:\frac {m ^ 2 * n ^ 5} {m * p ^ 4} =

Canceling common terms:

\frac {mn ^ 5} {p ^ 4}

Answer:

Option A

Question 2:

We should simplify the following expression:

\frac {3xyz ^ 2} {6y ^ 4} * \frac {2y} {xz ^ 4}

So, we have:

\frac {3xyz ^ 2 * 2y} {6y ^ 4 * xz ^ 4} =\\\frac {6xy ^ 2z ^ 2} {6y ^ 4xz ^ 4} =

Simplifying common terms:

\frac {1} {y ^ 2z ^ 2}

Answer:

Option D

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We factor the following expressions to rewrite the experience:

<em>r ^ 2 + 7r + 10: </em>We look for two numbers that multiplied give 10 and added 7:

(r + 5) (r + 2)

<em>r ^ 2-5r-50:</em> We look for two numbers that multiplied give -50 and added -5:

(r-10) (r + 5)

<em>3r-30 = 3 (r-10)</em>

Rewriting the given expression we have:

\frac {(r + 5) (r + 2) * 3 (r-10)} {3 (r-10) (r + 5)} =

We simplify common terms in the numerator and denominator we have:

(r + 2)

Answer:

Option D

4 0
3 years ago
Read 2 more answers
Can somebody explain to me how they got 3^4(x) = 3^3(x+2)? Then explain what happened to the 3 in 3^4 and the 3 in 3^3? Please a
musickatia [10]

Answer:

x=6

Step-by-step explanation:

81^x = 27 ^(x+2)

81 = 3^4    and 27 =3^3  so replace 81 and 27 in the equation

3^4^x = 3^3^(x+2)

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a^b = a^c   means b=c

4x = 3(x+2)

Now we can solve for x

Distribute

4x = 3x+6

Subtract 3x from each side

4x-3x = 3x-3x+6

x = 6

3 0
3 years ago
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