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Fittoniya [83]
3 years ago
10

Given f(x)=1/x+3 and g(x)=6/x+4, find the domain of f(g(x))

Mathematics
1 answer:
Murljashka [212]3 years ago
4 0

Answer:

The domain is all real numbers except the value of x=-6

Step-by-step explanation:

we have

f(x)=\frac{1}{x+3}

g(x)=\frac{6}{x+4}

we know that

f(g(x))=\frac{1}{(\frac{6}{x+4})+3}

f(g(x))=\frac{1}{\frac{6+3(x+4)}{x+4}}

f(g(x))=\frac{x+4}{6+3x+12}

f(g(x))=\frac{x+4}{3x+18}

f(g(x))=\frac{x+4}{3(x+6)}

Remember that the denominator cannot be equal to zero

so

The value of x cannot be equal to -6

therefore

The domain is all real numbers except the value of x=-6

In interval notation the domain is

(-∞,-6) ∪ (-6,∞)

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Step-by-step explanation:

Dont put the answer in parenthesis, I just did that to seprate it so it was easier to read. If you need it to be put in word form for it to be easier for you to understand, its "negative three divided by two x plus one, plus 3 divided by x minus 1"

First, rewrite the expression as 3x+6/2x^2+x-2x-1

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Then write terms in the numerators, for now we will use A and B.

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