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3 years ago

What is the greatest whole number that rounds to 277300

1 answer:

5 0

The answer is 300,000 because you have to round the bigger number that is 2 and don't forget to go next door and round 7 and that tell if it going up one more. We round 277,300 7 is more so add one more to the 2 and that is 300,000.

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PLZ ANSWER NUMBERS 8 AND 9. SHOWS YOUR WORK TOO!!!!

ASHA 777 [7]

8. 3x-4>38
3x>38+4
3x>42
x>42/3
x>14
So the answer is A. x>14

9. It's A. Two less than four times a number is 12. Because 4x (four times) and also it says 2 less than 4 times a number...

3 0

3 years ago

What does 3/216 simplify to

quester [9]

216 divided by 3 is 72 so making the answer

1/72

6 0

3 years ago

find x if the distance between points L and M is 15 and point M is located in the first quadrant. L=(-6,2) M=(x,2)

aivan3 [116]

Answer:

Therefore,

$x = 9$

Step-by-step explanation:

Given:

Let,

point L( x₁ , y₁) ≡ ( -6 , 2)

point M( x₂ , y₂ )≡ (x , 2)

l(AB) = 15 units (distance between points L and M)

To Find:

x = ?

Solution:

Distance formula between Two points is given as

$l(LM)^{2} = (x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}$

Substituting the values we get

$15^{2}=(x--6)^{2}+(2-2)^{2}\\\\225=(x+6)^{2}$

Square Rooting we get

$(x+6)=\pm \sqrt{225}=\pm 15\\\\x+6 = 15\ or\ x+6 = -15\\\\x= 9\ or\ x = -21$

As point M is located in the first quadrant

x coordinate and y coordinate are positive

So x = -21 DISCARDED

Hence,

$x = 9$

Therefore,

$x = 9$

3 0

3 years ago

The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of

mixer [17]

Notice the picture below

x = 1 and y = -1

now... recall your SOH CAH TOA $\bf sin(\theta)=\cfrac{y}{r}
\qquad 
% cosine
cos(\theta)=\cfrac{x}{r}
\qquad 
% tangent
tan(\theta)=\cfrac{y}{x}$

now.. what's the value for "r" or the radius? well, using the pythagorean theorem $\bf c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}\qquad 
\begin{cases}
a=x\\
b=y\\
c=r
\end{cases}$

6 0

3 years ago

The graph of which function will have a maximum and a y-intercept of 4? f(x) = 4x2 + 6x – 1 f(x) = –4x2 + 8x + 5 f(x) = –x2 + 2x

V125BC [204]

Answer:

Option C (f(x) = $-x^2 + 2x + 4$ )

Step-by-step explanation:

In this question, the first step is to write the general form of the quadratic equation, which is f(x) = $ax^2 + bx + c$ , where a, b, and c are the arbitrary constants. There are certain characteristics of the values of a, b, and c which determine the nature of the function. If a is a positive coefficient (i.e. if a>0), then the quadratic function is a minimizing function. On the other hand, a is negative (i.e. if a<0), then the quadratic function is a maximizing function. Since the latter condition is required, therefore, the first option (f(x) = $4x^2 + 6x - 1$ ) and the last option (f(x) = $x^2 + 4x - 4$ ) are incorrect. The features of the values of b are irrelevant in this question, so that will not be discussed here. The value of c is actually the y-intercept of the quadratic equation. Since the y-intercept is 4, the correct choice for this question will be Option C (f(x) = $-x^2 + 2x + 4$ ). In short, Option C fulfills both the criteria of the function which has a maximum and a y-intercept of 4!!!

7 0

3 years ago

Read 2 more answers