4\9=.444444444
answer=choice D
Answer:
Both equation represent functions
Step-by-step explanation:
The function is the relation that for each input, there is only one output.
A. Consider the equation

This equation represents the function, because for each input value x, there is exactly one output value y.
To check whether the equation represents a function, you can use vertical line test. If all vertical lines intersect the graph of the function in one point, then the equation represents the function.
When you intersect the graph of the function
with vertical lines, there will be only one point of intersection (see blue graph in attached diagram). So this equation represents the function.
B. Consider the equation

This equation represents the function, because for each input value x, there is exactly one output value y.
When you intersect the graph of the function
with vertical lines, there will be only one point of intersection (see green graph in attached diagram). So this equation represents the function.
Answer:
The answers are...:
The common ratio is -3
the sequence of the function is 2,-6, 18, -54, 162
and
the sequence of the function model is geometric
I hope this helps ^^"
Step-by-step explanation:
the common ratio is just from the -3 itself
the sequence model is just plugging n for every term so
a(1) would equal to 2, a(2)=-6 , a(3) would equal to -18, etc
and the geometric is bc it has the exponential that has (n-1), thus it is a geometric sequence
Given the next quadratic function:

to sketch its graph, first, we need to find its vertex. The x-coordinate of the vertex is found as follows:

where <em>a</em> and <em>b</em> are the first two coefficients of the quadratic function. Substituting with a = 2 and b = 3, we get:

The y-coordinate of the vertex is found by substituting the x-coordinate in the quadratic function, as follows:

The factorization indicates that the curve crosses the x-axis at the points (-2, 0) and (1/2, 0). We also know that the curve crosses the y-axis at (0,-2). Connecting these points and the vertex (-0.75, -3.125) with a U-shaped curve, we get:
There's nothing preventing us from computing one integral at a time:



Expand the integrand completely:

Then
