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3 years ago

Please don’t skip over me! show all work

Mathematics

1 answer:

aleksklad [387]3 years ago

7 0

Answer:

a,c,d

Step-by-step explanation:

$a. \\4i^9+4i^7\\=4i(i^2)^4+4i(i^2)^3\\=4i(-1)^4+4i(-1)^3\\=4i-4i\\=0\\b.\\2i^{18}-3i^{11}\\=2(i^2)^9-3i(i^2)^5\\=2(-1)^9-3i(-1)^5\\=-2+3i\\c.\\7i^{36}-11i^{11}-11i^9\\=7(i^2)^{18}-11i(i^2)^5-11i(i^2)^4\\=7(-1)^{18}-11i(-1)^5-11i(-1)^4\\=7+11i-11i\\=7\\d.\\8i^{22}-1\\=8(i^2)^{11}-1\\=8(-1)^{11}-1\\=-8-1\\=-9$

$2i^{27}+4\\=2i(i^2)^{13}+4\\=2i(-1)^{13}+4\\=-2i+4$

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The future value can be computed using the formula for an annuity due. It can also be found using any of a variety of calculators, apps, or spreadsheets.

<h3>formula</h3>

The formula for the value of an annuity due with payment P, interest rate r, compounded n times per year for t years is ...

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<h3>calculator</h3>

The attached calculator screenshot shows the same result. The calculator needs to have the begin/end flag set to "begin" for the annuity due calculation.

The future value of the annuity due is $66,184.15.

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