Question

Please don’t skip over me! show all work

Answer 1

Answer:

a,c,d

Step-by-step explanation:

$a. \\4i^9+4i^7\\=4i(i^2)^4+4i(i^2)^3\\=4i(-1)^4+4i(-1)^3\\=4i-4i\\=0\\b.\\2i^{18}-3i^{11}\\=2(i^2)^9-3i(i^2)^5\\=2(-1)^9-3i(-1)^5\\=-2+3i\\c.\\7i^{36}-11i^{11}-11i^9\\=7(i^2)^{18}-11i(i^2)^5-11i(i^2)^4\\=7(-1)^{18}-11i(-1)^5-11i(-1)^4\\=7+11i-11i\\=7\\d.\\8i^{22}-1\\=8(i^2)^{11}-1\\=8(-1)^{11}-1\\=-8-1\\=-9$

e.

$2i^{27}+4\\=2i(i^2)^{13}+4\\=2i(-1)^{13}+4\\=-2i+4$