A tree farming company is testing how many items customers purchase during their visits. Based on many results, the (partial) pr
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All these cases represent experiments whose outcomes are all equaly likely. What we mean is that the cards have all the same probability of being dealt (1/52), and all the spaces of the spinner have the same probability of being landed into (1/5).
These probabilities are computed as 1 over all the possible outcomes.
(a) If you want a heart card and a five, you want the 5 of hearts. So, only one card would satisfy your request, and thus you have probability 1/52 of dealing the 5 of hearts.
(b) There are four 10s and four Jacks in the deck, so 8 cards satisfy your request. With probability 8/52, you'll be dealt a Jack or a 10.
(c) You have two "good" outcomes out of 5, so your probability is 2/5.
The value of zu(1,3) using the data elements represented on the table of values is q + p
<h3>How to solve the calculus expression?</h3>The given parameters are:
z = f(x, y)
x = x(u, v)
y = y(u, v)
Where
x(1, 3) = 2 and y(1, 3) = 2
To calculate zu(1,3), we make use of:
The values x(1, 3) = 2 and y(1, 3) = 2 mean that:
(x,y) = (2,2).
So, we have:
From the table of values, we have:
So, the equation becomes
Evaluate the product
Hence, the value of zu(1,3) is q + p
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