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2 years ago

Vertical angles must:

Mathematics

2 answers:

katen-ka-za [31]2 years ago

8 0

Answer:

A. Be congruent

C. Be have the same vertex

Step-by-step explanation:

Vertical angles are those angles that share the same vertex.

If the vertical angles are formed when two lines intersect in a plane, then they are opposite angles. That means they are congruent.

Mice21 [21]2 years ago

7 0

Vertical angles must be, out of the options stated, A ) congruent and C ) have the same vertex

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Hi I need help :( Pls show your working..Will give brainliest for helpful answer

Basile [38]

Answer:

number 10

dy/dx =(dy/dt).(dt/dx)

now find

dy/dt=4t-1. , dt/dx=1

so : dy/dx=(4t-1).(1)

dy/dx= 4t-1 ,we have x=t-3-----> t=x+3

subtitute at t

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3 years ago

If (8^9)p = 8^16 what's the value of p?

monitta

Answer:

$p = {8}^{7}$

Step-by-step explanation:

$(8^9)p = 8^{16 } \\ \\ p = \frac{8^{16 } }{8^{9 } } \\ \\ p = {8}^{16 - 9} \\ \\ \huge \red{ \boxed{p = {8}^{7} }}$

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2 years ago

What does COP mean? How do you execute it?

Rzqust [24]

Answer:

COP: Coefficient Of Performance

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2 years ago

I need help with this problem

Arada [10]

Answer:

65.56°

Step-by-step explanation:

We know that if we take dot product of two vectors then it is equal to the product of magnitudes of the vectors and cosine of the angle between them

That is let p and q be any two vectors and A be the angle between them

So, p·q=|p|*|q|*cosA

⇒ $cosA=\frac{u.v}{|u||v|}$

Given u=-8i-3j and v=-8i+8j

$|u|=\sqrt{(-8)^{2}+ (-3)^{2}} =8.544$

$|v|=\sqrt{(-8)^{2}+ (8)^{2}} =11.3137$

let A be angle before u and v

therefore, $cosA=\frac{u.v}{|u||v|}=\frac{(-8)*(-8)+(-3)*(8)}{8.544*11.3137} =\frac{40}{96.664}$

⇒ $A=arccos(\frac{40}{96.664} )=arccos(0.4138 )=65.56$

Therefore angle between u and v is 65.56°

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2 years ago

Need geometry genius

IRISSAK [1]

Answer is D.

Last one...

hope it helps

8 0

2 years ago