The slope of line passing through the points (4, 4) and (10, 7) is 
<em><u>Solution:</u></em>
Given that, we have to find the slope of line that passes through the points (4, 4) and (10, 7)
The slope of line passing through 
and 
is given as:
Given two points are (4, 4) and (10, 7)
Substituting the values in formula, we get
Reducing to lowest terms, we get
Thus slope of line passing through given points is
Answer:
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Step-by-step explanation:
Answer:
A. 50.24
Step-by-step explanation:
C=2πr=2·π·8=50.24
When you have an irregular figure, you can divide it so that it becomes multiple normal figures. You already did this in the picture, now you just have to find the area of each shape and then add them all together.
From bottom to top:
A=1/2 (b1+b2)h
A= 1/2 (4+2.24)(2)
A= 6.24
(you have two of these on either side)
A=bh
A=6(4)
A=24
A=1/2 bh
A= 1/2 (4)(4)
A=8
(NOTE: there is an error in your drawing. The height of the triangle cant be determined because the 10 value spans over the entire figure when the wings of the rocket are 4 units long and then the body is 6 units long, making it equal 10 already. I'm assuming that the 10 is supposed to go from the bottom of the rectangle to the top of the triangle)
Total figure= 6.24 + 6.24 + 24 + 8
total figure = 44.48
Answer:
6
Step-by-step explanation:
(x^10)^3/5
=x^(10×3/5)
=x^6
