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2 years ago

How do you use subtraction to find a missing addend in an addition problem? Explain

1 answer:

4 0

You basically just get a equation that needs to be answered and grab the answer and minus it by one of the two digits in front. Example: 3+2=5 is equal to 5-2=3

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Solve the following system of equations algebraically:<br> 4x - 5y = 18<br> 3x – 2y = 10

fiasKO [112]

Answer:

Step-by-step explanation:

Given the 2 equations

4x - 5y = 18 → (1)

3x - 2y = 10 → (2)

Multiplying (1) by 3 and (2) by - 4, then adding will eliminate the x- term

12x - 15y = 54 → (3)

- 12x + 8y = - 40 → (4)

Add (3) and (4) term by term to eliminate x, that is

- 7y = 14 ( divide both sides by - 7 )

y = - 2

Substitute y = - 2 into either of the 2 equations and solve for x

Substituting into (1)

4x - 5(- 2) = 18

4x + 10 = 18 ( subtract 10 from both sides )

4x = 8 ( divide both sides by 4 )

x = 2

solution is (2, - 2 ) → D

8 0

3 years ago

A jar holds 128 fluid ounces of juice. The label says the jar has 16 servings. How many fluid ounces are needed for 80 servings?

Bumek [7]

There are 16 servings for each 128 fluid ounces of juice.

Divide 80 servings by 16 servings, and 5 should be the quotient. Therefore, there are 5 jars of juice. Multiply 128 by 5 since 128 fluid ounces are in one jar. The answer should be 640 fluid ounces.

8 0

3 years ago

Read 2 more answers

What is the third quartile, Q3, of the following distribution?

GREYUIT [131]

Answer:

The third quartile is:

$Q_3=29$

Step-by-step explanation:

First organize the data from lowest to highest

4, 5, 10, 12, 14, 16, 18, 20, 21, 21, 22, 22, 24, 26, 29, 29, 33, 34, 43, 44

Notice that we have a quantity of n = 20 data

Use the following formula to calculate the third quartile $Q_3$

For a set of n data organized in the form:

$x_1, x_2, x_3, ..., x_n$

The third quartile is $Q_3$ :

$Q_3=x_{\frac{3}{4}(n+1)}$

With n=20

$Q_3=x_{\frac{3}{4}(20+1)}$

$Q_3=x_{15.75}$

The third quartile is between $x_{15}=29$ and $x_{16}=29$

Then

$Q_3 =x_{15} + 0.75*(x_{16}- x_{15})$

$Q_3 =29 + 0.75*(29- 29)\\\\Q_3 =29$

5 0

3 years ago

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Find the probability of a least one birthday match among a group of 44 people.

Cerrena [4.2K]

Answer:

0.1137= 11.37%

Step-by-step explanation:

Assuming there are 365 days in one year and every people have 1 birthday, then the chance for two people to have the same birthday is 1/365 and the chance they are not is 364/365. We are asked the chance for at least one match among 44 people. The opposite of the condition is that we have 0 matches and easier to calculate. The calculation will be:

P(X>=1)= ~P(X=0) = 1

P(X>=1)=- P(X=0)

P(X>=1)=1 - (364/365)^44

P(X>=1)=1- 0.8862

P(X>=1)=11.37%

3 0

3 years ago

What is the value of -16?

timama [110]

Answer:

the answer would be -4

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers