Answer:
Explanation:
First, I plotted both the lines on the graph, then I graphed the inequality.<u> </u><em>Please check out image.</em> Looking at the image, we can tell that the graph matches with Graph-C. Hence, Option C is correct.
Hoped this helped!
The answer is 4^3 and I believe that this is right
Answer: I'll help you, but where is the question?
Step-by-step explanation:
Answer:
Step-by-step explanation:
a.
slope=-1/2
b.
eq. of line is
y-0=(-2-0)/(0-(-2)(x-(-2))
y=-2/2 (x+2)
or y=-x-2
Answer:
- Solution of equation ( x ) = <u>7</u>
Step-by-step explanation:
In this question we have given with an equation that is <u>4</u><u> </u><u>(</u><u> </u><u>5</u><u>x</u><u> </u><u>-</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>(</u><u> </u><u>9</u><u>x</u><u> </u><u>+</u><u> </u><u>3 </u><u>)</u><u>.</u> And we are asked to solve this equation that means we have to find the value of <u>x</u><u>.</u><u> </u>
<u>Solution</u><u> </u><u>:</u><u> </u><u>-</u>
<u>
</u>
<u>Step </u><u>1</u><u> </u><u>:</u> Removing parenthesis :

<u>Step </u><u>2</u><u> </u><u>:</u> Adding 8 from both sides :

On further calculations we get :

<u>Step </u><u>3 </u><u>:</u> Subtracting 18 from both sides :

On further calculations we get :

<u>Step </u><u>4</u><u> </u><u>:</u> Dividing with 2 on both sides :

On further calculations we get :

- <u>Therefore</u><u>,</u><u> </u><u>solution</u><u> </u><u>of </u><u>this </u><u>equation</u><u> </u><u>is </u><u>7</u><u> </u><u>or </u><u>we </u><u>can </u><u>say </u><u>that </u><u>value </u><u>of </u><u>this </u><u>equation</u><u> </u><u>is </u><u>7</u><u> </u><u>.</u>
<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>
We are verifying our answer by substituting value of x in given equation. So ,
- 4 ( 5x - 2 ) = 2 ( 9x + 3 )
- 4 [ 5 ( 7 ) - 2 ] = 2 [ 9 ( 7 ) + 3 ]
- 4 ( 35 - 2 ) = 2 ( 63 + 3 )
<u>Therefore</u><u>,</u><u> </u><u>our </u><u>value</u><u> for</u><u> x</u><u> is</u><u> </u><u>correct </u><u>.</u>
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<u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>