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12345 [234]
3 years ago
9

3(d-8)=9(d+2) Please help

Mathematics
2 answers:
Bezzdna [24]3 years ago
3 0
The answer is d=-7 because i did the math
Furkat [3]3 years ago
3 0

Answer: d = -7

Step-by-step explanation:

Let's solve your equation step-by-step.

3(d−8)=9(d+2)

Step 1: Simplify both sides of the equation.

3(d−8)=9(d+2)

(3)(d)+(3)(−8)=(9)(d)+(9)(2)(Distribute)

3d+−24=9d+18

3d−24=9d+18

Step 2: Subtract 9d from both sides.

3d−24−9d=9d+18−9d

−6d−24=18

Step 3: Add 24 to both sides.

−6d−24+24=18+24

−6d=42

Step 4: Divide both sides by -6.

−6d

−6

=

42

−6

d=−7

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Help me with this and I have to show my work
Naddik [55]
223.6 divided by 40 equals 5.59
7 0
4 years ago
Consider the following statement: ∀ a, b, c ∈ Z, if a − b is even and b − c is even, then a − c is even.
kirill115 [55]

Answer Step-by-step explanation:

Given statement if a-b is even and b-c is even then a-c is even .

Let p: a-b and b-c are even

q: a-c is even.

Converse: If a-c is even then a-b and b-c are both even.

Inverse:If a-b and b-c  are not both even then a-c is not even.

If a= Even number

b= Even number

c=Even number

If a-c  is even then a-b and b-c are both even..Hence, the converse statement is true.

If a=Odd number

b=Odd number

c= Odd number

If a-c is even then a-b and b-c are both even number .Hence, the converse  statement is true.

If a=Even number

b= Even number

c= Odd number

a-b  and b-c are both odd not even number but a-c is even number

a=8,b=6 c=3

a-b=8-6=2

b-c=6-3=3

a-c=8-3=5

If a-c is odd then a-b even but b-c is odd .Hence , the converse statement is false.But the inverse statement is true.

If a= Odd number

b=Even number

c= Even number

If a-b is odd and b-c is even then a-c is odd not even . Hence, the inverse statement is true.

If a= Odd number

b=Eve number

c=Odd number

a=9,b=6,c=5

a-b=9-6=3

b-c=6-5=1

a-c=9-5=4

Here, a-b and b-c are not both even but a-c is even .Hence, the inverse statement is false.

4 0
4 years ago
Find the domain and range of the function:<br> f(t)=sec[((pi)t)/4]
beks73 [17]

The domain and range of the function f(t)=sec[((pi)t)/4] are the following:

<span>Domain: All the real numbers except t = 2 + 4k, where k is an integer. </span>

Range: (-∞, -1] U [1, ∞)

I am hoping that these answers have satisfied your queries and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

3 0
4 years ago
A digital scale reports a 10kg weight as weighing 8.975kg. which of the following is true?
lukranit [14]
That question is accompanied by these answer choices:

<span>A. The scale is accurate but not precise.
B. The scale is precise but not accurate.
C. The scale is neither precise nor accurate.
D. The scale is both accurate and precise.

Then you need to distinguish between accuracy and precision.

Accuracy refers to the closeness of the measure to the real value, while precision, in this case, refers to the level of significant figures that the sacle report.

The fact that the scale reports the number with 4 significant figures means that it is very precise, but the fact that the result is not so close to the real value as the number of significan figures pretend to be, means that the scale is not accurate.

So, the answer is that the scale is precise but not accurate (the option B).
</span>
6 0
3 years ago
What is the distance between the points (2, -3) and (-6, 4) on the coordinate
VikaD [51]

Answer:

C) 10.63 units.

Step-by-step explanation:

To find the distance between any two points, we can use the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have the two points (2, -3) and (-6, 4). Let (2, -3) be (<em>x₁, y₁</em>) and let (-6, 4) be (<em>x₂, y₂</em>). Substitute:

d=\sqrt{(-6-2)^2+(4-(-3))^2}

Simplify:

d=\sqrt{(-8)^2+(7)^2}

Evaluate:

d=\sqrt{64+49}=\sqrt{113}\approx10.63\text{ units}

Our answer is C.

7 0
3 years ago
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