Answer:
Option B) 3.04
Step-by-step explanation:
We are given the following in the question:
Number of people interviewed,n = 163
Number of people hire, x = 121
Proportion of people hire =
![\dfrac{x}{n} = \dfrac{121}{163} = 0.742](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%7D%7Bn%7D%20%3D%20%5Cdfrac%7B121%7D%7B163%7D%20%3D%200.742)
Mean, μ = 3.3
Standard Deviation, σ = 0.4
We are given that the distribution of GPA for the successful interviewees is a bell shaped distribution that is a normal distribution.
Formula:
![z_{score} = \displaystyle\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z_%7Bscore%7D%20%3D%20%5Cdisplaystyle%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
We have to find the value of x such that the probability is 0.742
Calculation the value from standard normal z table, we have,
Thus, cut-off GPA should be 3.04.
Option B) 3.04