It takes Joey 1/16 of an hour to write one Thank You card.How many cards can he write in 3/4 of an hour?

What is the slope of the line through (2,5) and (-1,2)?

Luden [163]

Answer:

The slope of the line is m = 1

Step-by-step explanation:

Slope is essentially change in height over change in horizontal distance, and is often referred to as "rise over run." It has applications in gradients in geography as well as civil engineering, such as the building of roads. In the case of a road the "rise" is the change in altitude, while the "run" is the difference in distance between two fixed points, as long as the distance for the measurement is not large enough that the earth's curvature should be considered as a factor. The slope is represented mathematically as:

m = y2-y1 / x2-x1

m = 2 - 5 / -1 - 2

m = -3 / -3

m = 1

X1 is 2

Y1 is 5

X2 is -1

Y2 is 2

6 0

3 years ago

5) Two machines M1, M2 are used to manufacture resistors with a design

Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that $\mu = 1050, \sigma = 100$

The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So

X = 1100

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1100 - 1050}{100}$

$Z = 0.5$

$Z = 0.5$ has a pvalue of 0.6915.

X = 900

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{900 - 1050}{100}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

0.6915 - 0.0668 = 0.6247.

M1 has a 62.47% probability of being in the desired range.

M2:

M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that $\mu = 1000, \sigma = 120$

X = 1100

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1100 - 1000}{120}$

$Z = 0.83$

$Z = 0.83$ has a pvalue of 0.7967.

X = 900

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{900 - 1000}{120}$

$Z = -0.83$

$Z = -0.83$ has a pvalue of 0.2033

0.7967 - 0.2033 = 0.5934

M2 has a 59.34% probability of being in the desired range.

Since M1 has the higher probability of being in the desired range, we choose M1.

8 0

3 years ago

An electronics company makes communication devices for military contracts. The company just completed two contracts. The navy co

adelina 88 [10]

Answer:

Workers of army contract were more productive.

Step-by-step explanation:

To determine on which contract the workers were more productive compute the work done per hour by the workers for both contracts.

<u>Navy Contract</u>:

Number of devices = 2,300

Number of workers = 25

Number of weeks = 2 weeks

Number of hours per week = 40

The number of hours it took 25 workers to produce 2300 devices is =

$=25\times2\times40\\=2000\ hours$

Then number of devices produced in 1 hour is = $\frac{2300}{2000}= 1.15\ devices\ per\ hour$

<u>Army Contract</u>:

Number of devices = 5,500

Number of workers = 35

Number of weeks = 3 weeks

Number of hours per week = 40

The number of hours it took 35 workers to produce 5500 devices is = $=35\times3\times40\\=4200\ hours$

Then number of devices produced in 1 hour is = $\frac{5500}{4200}= 1.31\ devices\ per\ hour$

The workers for the army contract are more productive since they produce 1.31 devices per hour whereas the workers for navy contract produces 1.15 devices per hour.

4 0

3 years ago

Production times are evenly distributed between 8 and 15.8 minutes and production times are never outside of this interval. What

dezoksy [38]

Answer:

29.49% probability that a production time is between 9.7 and 12 minutes

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X between c and d, in which d is greater than c, is given by the following formula.

$P(c \leq X \leq d) = \frac{d - c}{b-a}$