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Sophie [7]
2 years ago
15

What is 4x less than or equal to 12

Mathematics
1 answer:
mihalych1998 [28]2 years ago
8 0
3 x 4 is equal to 12 I think that’s your answer
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Which of the following is not the same as 1.69 meters? 0.0169 km 0.169 dkm 169 cm 1,690 mm
bezimeni [28]

Answer:

0.0169 km.

Step-by-step explanation:

km - kilometers (One kilometer is equal to 1000 meters.)

dkm - dekameters (One dekameter is equal to 10 meters.)

cm - centimeters (One centimeter is equal to 0.01 meters.)

mm - millimeters (One millimeter is equal to 0.1 meters.)

Used a calc to check each of the values to see if they equal 1.69m and km was the one that wasn't equal. Instead it was 16.9.

3 0
3 years ago
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Hal has 24 video games 6 if his games are sports related and the rest are role playing games which ratio represent the number of
Natali [406]

Answer:

It would be 18;24 or simplified it would be 3;4

Step-by-step explanation:

24-6=18 so there are 18 role playing games. So the ratio could be 18;24 but if it needs to be simplified you can divide both numbers by 6. 18/6=3 and 24/6=4

4 0
3 years ago
Shari wrote the numbers from 1 to 16 on a card.
-BARSIC- [3]
Factors of 80: 1,2,4,5,8,10,16,20,40,80
so we cross out 1,2,4,5,8,10,16
the first 5 multiples of 3 are: 3,6,9,12,15
so we cross out those number and then we are left with 7, 11, 13 and 14
the answer is: 4 numbers were not crossed out
8 0
3 years ago
Need helppp asap!!!!!!!!
navik [9.2K]

D. 73


dis is your answer

7 0
3 years ago
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The mean and standard deviation of a random sample of n measurements are equal to 34.5 and 3.4, respectively.A. Find a 95 % conf
lora16 [44]

Answer:

a. The 95% confidence interval for the mean is (33.52, 35.48).

b. The 95% confidence interval for the mean is (34.02, 34.98).  

c. n=49 ⇒ Width = 1.95

n=196 ⇒ Width = 0.96

Note: it should be a factor of 2 between the widths, but the different degrees of freedom affects the critical value for each interval, as the sample size is different. It the population standard deviation had been used, the factor would have been exactly 2.

d. 5. Quadrupling the sample size while holding the confidence coefficient fixed decreases the width of the confidence interval by a factor of 2.

Step-by-step explanation:

a. We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=34.5.

The sample size is N=49.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{3.4}{\sqrt{49}}=\dfrac{3.4}{7}=0.486

The degrees of freedom for this sample size are:

df=n-1=49-1=48

The t-value for a 95% confidence interval and 48 degrees of freedom is t=2.011.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.011 \cdot 0.486=0.98

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 34.5-0.98=33.52\\\\UL=M+t \cdot s_M = 34.5+0.98=35.48

The 95% confidence interval for the mean is (33.52, 35.48).

b. We have to calculate a 95% confidence interval for the mean.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{3.4}{\sqrt{196}}=\dfrac{3.4}{14}=0.243

The degrees of freedom for this sample size are:

df=n-1=196-1=195

The t-value for a 95% confidence interval and 195 degrees of freedom is t=1.972.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=1.972 \cdot 0.243=0.48

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 34.5-0.48=34.02\\\\UL=M+t \cdot s_M = 34.5+0.48=34.98

The 95% confidence interval for the mean is (34.02, 34.98).

c. The width of the intervals is:

n=49\rightarrow UL-LL=33.52-35.48=1.95\\\\n=196\rightarrow UL-LL=34.02-34.98=0.96

d. The width of the intervals is decreased by a factor of √4=2 when the sample size is quadrupled, while the others factors are fixed.

8 0
3 years ago
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