The right angled triangle is missing, so i have attached it.
Answer:
Proved below
Step-by-step explanation:
From the attached image, we can see that QP is parallel to BC.
Now, looking at triangles AQP and ABC, we can see that;
∠ AQP = ∠ ABC
Also;
∠ APQ = ∠ ACB
This means that triangles ABC and AQP are similar.
We are told that P is the mid-point of AC.
Thus; AP = PC
We can now say that;
AP:AC = 1:2 and AQ:AB = 1:2
Since AQ:AB = 1:2, it means Q is the midpoint of AB.
Now, ∠ AQP = ∠ BQP
However, according to SAS congruence test, AQP is congruent to BQP.
Thus; AP = BP = CP
Since AP:AC = 1:2 as we saw earlier, then;
BP:AC = 1:2
Thus:
BP/AC = ½
BP = ½AC
Choose 2 points and then the x will be like 3 and the y -3 and the equation y = 3x-3
The answer for number 5 is $132 because 36/3=12,12*11=132
Number 6 is 8.4 minutes 8.4*10=84
For the sake of solving, temporarily replace the < sign with an = sign. Solve as you normally would.
3 + d = 3 - d
add d to both sides
3 + 2d = 3
Subtract 3 from both sides
2d = 0
Now replace the = sign with the < sign again.
2d < 0
Divide both sides by 2 to get your final answer.
d < 0
If you are ever uncertain with an answer to an inequality, the best thing to do is plug in a random number! (In this case, make sure the number is less than 0)
3 + (-1) < 3 - (-1)
3 - 1 < 3 + 1
2 < 4
(-1) is less than zero, and when plugged into the inequality the values of the left side is less than the value of the right side. This shows that d IS < 0.