11.5% × 350 =
(11.5 ÷ 100) × 350 =
(11.5 × 350) ÷ 100 =
4,025 ÷ 100 =
40.25
Double is double, so you can solve
.. 2 = 1*e^(.08t)
and get the correct value of t.
Taking logs,
.. ln(2) = .08t
.. ln(2)/.08 = t ≈ 8.7 . . . . years
Answer: 15309
hope this helps, the nth term calulation is (7/3) times 3^n
The answer is 5/3 can I have the some points
Answer:
88
Step-by-step explanation:
Given:
(h⁴ + h² – 2) ÷ (h + 3).
We could obtain the remainder using the remainder theorem :
That is the remainder obtained when (h⁴ + h² – 2) is divided by (h + 3).
Using the reminder theorem,
Equate h+3 to 0 and obtain the value of h at h+3 = 0
h + 3 = 0 ; h = - 3
Substituting h = - 3 into (h⁴ + h² – 2) to obtain the remainder
h⁴ + h² – 2 = (-3)⁴ + (-3)² - 2 = 81 + 9 - 2 = 88
Hence, remainder is 88
