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mario62 [17]
2 years ago
14

In the system –12c + 3d = 6 and –3c + 6d = –9, which expression could you use for substitution?

Mathematics
1 answer:
Jlenok [28]2 years ago
5 0
3d is the answer if I am wrong please let me know

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Why is scientific notation used?
scoray [572]
The answer is the last one; to express very large or small numbers.
We use it so we can show big or very small numbers in an easier way.
6 0
3 years ago
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What is the distance between (4,7) and (2,2)?
algol [13]
\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ 4}}\quad ,&{{ 7}})\quad 
%  (c,d)
&({{ 2}}\quad ,&{{ 2}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
d=\sqrt{(2-4)^2+(2-7)^2}\implies d=\sqrt{(-2)^2+(-5)^2}
\\\\\\
d=\sqrt{4+25}\implies d=\sqrt{29}
7 0
2 years ago
Use your knowledge about parentheses and substitution to solve the following:
meriva

Answer:

16. r(s)(t) =

r=2, s=3, t=4

(2)(3)(4)=

             (2*3) = 6  ---> 6(4) = 24

final: 24

17. (r)(s)(t)(x)(y) =

r = 2, s = 3, t = 4, x = 5, y = 6

(2)(3)(4)(5)(6)

2*3=6

      6*4=24

            24*5= 120

                     120*6=720

final: 720

18. (7x + 2Y) =

x = 5, y = 6

rewrite--->        = [7(5) + 2(6)]

[35 + 12] = 47

final: 47

hope this helpsss sorry took a while LOL

Step-by-step explanation:

q = 1; r = 2; s = 3; t = 4; x = 5; y = 6

5 0
2 years ago
Read 2 more answers
Jacinta, an internet website designer, works a 38 hour week and earns $3115.35 every fortnight. Calculate her earnings:
sveticcg [70]

Step-by-step explanation:

total working duration = 2 weeks

Working duration in hours = 38× 2= 76 hours

a) per year

24*3115.35 = $74768

b) 3115.35/2

$1557.675

c)

3115.35/76

$40.99

6 0
3 years ago
Read 2 more answers
PLEASEEE I DONT KNOW HOW TO DO ITTTT. THE 35.8 IS RIGHT BUT I CANT GET MEASURE OF ANGLE C AND A I GOT 46.2 for A AND 70.8 for C
Rashid [163]

Answer:

Hope it helps....!!!!!

Step-by-step explanation:

AB = c = 38

BC = a = 29

AC = b

Angle ABC = 63 degrees

Solving for AC   "b":

Cosine rule: c^2 = a^2 * b^2 -2ab * cos C

38^2 = 29^2 * b^2 - (2* 29) * b * (cos 38)

1444 = 841 * b^2 - 58 * b * 0.955

(1444 + 58)/0.955 = b^2 * b

1572.77486911 = b^3

11.62935 = b

11.63 = b (rounded to two decimal places)

Now solving for angle A:

Sine rule: a/sinA = b/sinB

29/sinA = 11.63/sin(63)

sinA/29 = sin(63)/11.63

sin A = (sin(63)/11.63) * 29

sin A = 0.41731

A = sin^-1 (0.41731)

A = 24 degrees 39 minutes 53 seconds

Now solving for angle C:

Sine rule: c/sinC = b/sinB

38/sinC = 11.63/sin(63)

sinC/38 = sin(63)/11.63

sin C = (sin(63)/11.63) * 38

sin C = 0.54682

C = sin^-1 (0.54682)

C = 33 degrees 8 minutes 56 seconds

3 0
3 years ago
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