The answer is the last one; to express very large or small numbers.
We use it so we can show big or very small numbers in an easier way.
Answer:
16. r(s)(t) =
r=2, s=3, t=4
(2)(3)(4)=
(2*3) = 6 ---> 6(4) = 24
final: 24
17. (r)(s)(t)(x)(y) =
r = 2, s = 3, t = 4, x = 5, y = 6
(2)(3)(4)(5)(6)
2*3=6
6*4=24
24*5= 120
120*6=720
final: 720
18. (7x + 2Y) =
x = 5, y = 6
rewrite---> = [7(5) + 2(6)]
[35 + 12] = 47
final: 47
hope this helpsss sorry took a while LOL
Step-by-step explanation:
q = 1; r = 2; s = 3; t = 4; x = 5; y = 6
Step-by-step explanation:
total working duration = 2 weeks
Working duration in hours = 38× 2= 76 hours
a) per year
24*3115.35 = $74768
b) 3115.35/2
$1557.675
c)
3115.35/76
$40.99
Answer:
Hope it helps....!!!!!
Step-by-step explanation:
AB = c = 38
BC = a = 29
AC = b
Angle ABC = 63 degrees
Solving for AC "b":
Cosine rule: c^2 = a^2 * b^2 -2ab * cos C
38^2 = 29^2 * b^2 - (2* 29) * b * (cos 38)
1444 = 841 * b^2 - 58 * b * 0.955
(1444 + 58)/0.955 = b^2 * b
1572.77486911 = b^3
11.62935 = b
11.63 = b (rounded to two decimal places)
Now solving for angle A:
Sine rule: a/sinA = b/sinB
29/sinA = 11.63/sin(63)
sinA/29 = sin(63)/11.63
sin A = (sin(63)/11.63) * 29
sin A = 0.41731
A = sin^-1 (0.41731)
A = 24 degrees 39 minutes 53 seconds
Now solving for angle C:
Sine rule: c/sinC = b/sinB
38/sinC = 11.63/sin(63)
sinC/38 = sin(63)/11.63
sin C = (sin(63)/11.63) * 38
sin C = 0.54682
C = sin^-1 (0.54682)
C = 33 degrees 8 minutes 56 seconds
