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3 years ago

Break apart the addends to find the sum 18+21

1 answer:

3 0

We break apart the first numer:

10+8

the second:

20+1

and add like this:

18+21=10+8 + 20+1

now, we can mix up the order:

18+21=10+8 + 20+1= 10+20 + 8+1

add the parts:

18+21=10+8 + 20+1= 10+20 + 8+1=30+9=39

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( 3m - 2 ) + 2 - m + 3

tia_tia [17]

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Step-by-step explanation:

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7 0

3 years ago

PLZ HELP SCALE FACTOR TRIANGLE A. 10.5 cm B. 31.5 cm C. 63 cm D. 189 cm

Anarel [89]

If two similar triangles have sides in the ratio a : b, then their areas are in the ratio a² : b².

We have the ratio:

$54:18=\dfrac{54}{18}=3:1$

Area of the smaler triangle = x

Area of the larger triangle = 567 cm²

Therefore we have the equation:

$567:x=3^2:1^2\\\\\dfrac{567}{x}=\dfrac{9}{1}\qquad|\text{cross multiply}\\\\9x=567\qquad|\text{divide both sides by 9}\\\\x=63$

<h3>Answer: C. 63 cm²</h3>

3 0

3 years ago

Help meeeeeeeeeee Help meee

Alinara [238K]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A right rectangular prism has a length of 10 centimeters, a width of 2.5 centimeters and a height of 0.9 centimeters what is the

nikdorinn [45]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{22.5 \: {cm}^{3} }}}}}$

Step-by-step explanation:

Given,

Length of a rectangular prism ( l ) = 10 cm

Width of a rectangular prism ( w ) = 2.5 cm

Height of a rectangular prism ( h ) = 0.9 cm

Volume of a rectangular prism ( V ) = ?

Finding the volume of a rectangular prism

$\boxed{ \bold{ \sf{volume \: of \: a \: rectangular \: prism = lwh}}}$

$\dashrightarrow{ \sf{volume = 10 \times 2.5 \times 0.9}}$

$\dashrightarrow{ \sf{volume = 22.5 \: {cm}^{3} }}$

Hope I helped!

Best regards! :D

7 0

3 years ago

Which expression is equivalent to ( 4mn / m^-2n^6)^-2a. n^6 / 16m^8b. n^10 / 16m^6c. n^10 / 8m^8d. 4m^3 / n^8?

Eva8 [605]

$\huge{(} \small{\frac{4mn}{ {m}^{ - 2} {n}^{6} }} \huge{) } \small{{}^{ {}^{ {}^{ {}^{ - 2} } } } }\\ \\ \\ \huge{(} \small{ \frac{4 \times m {}^{1} \times n {}^{1} }{ {m}^{ - 2} \times {n}^{6} }} \huge{)} \small{^{ {}^{ {}^{ {}^{ - 2} } } }} \\ \\ \\ \huge{(} \small{4 \times {m}^{1 - ( - 2)} \times {n}^{1 - 6}} \huge{)} \small{ {}^{ {}^{ {}^{ {}^{ - 2} } } } } \\ \\ \\ \huge{(} \small{ 4 \times {m}^{1 + 2} \times {n}^{ - 5} } \huge{)} \small{ { }^{ {}^{ {}^{ {}^{ - 2} } } } } \\ \\ \\ \small{ {(4)}^{ - 2} \times ({m}^{3} ) ^{ - 2} \times {(n{}^{ - 5} )}^{ - 2} } \\ \\ \\ \frac{1}{ {4}^{2} } \times {m}^{ - 6} \times {n}^{ 10} \\ \\ \\ \frac{1}{16} \times \frac{1}{ {m}^{6} } \times {n}^{10} \\ \\ \\ \frac{ {n}^{10} }{16{m}^{6} }$

$\text{ Hence, option B is correct }$

7 0

4 years ago