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Serggg [28]
2 years ago
9

When 334 college students are randomly selected and surveyed, it is found that 103 own a car. Find a 99% confidence interval for

the true proportion of all college students who own a car.
Mathematics
1 answer:
NemiM [27]2 years ago
8 0

Answer:

(.24329, .3734)

Step-by-step explanation:

1-propzint

n=334

x=103

c level .99

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How many solutions will there be to the following equation?16x^2=100
djverab [1.8K]

Answer:

2 solutions; x=2.5     x=-25

Step-by-step explanation:

16x^2 = 100

x^2 = 100/16

x^2 = 6.25

x = (+-) sqrt 6.25

x = (+-) 2.5

4 0
2 years ago
Algebra Find the values for x and y in parallelogram ABCD. AE= 2x, EC=y+4, DE=x, EB=2y-1. AC and BD intersect at point E
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6 0
3 years ago
If you roll a fair die 100 times and 35 of the rolls result in a two, what would be the probability of the outcome of a 2,
EastWind [94]

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56

Step-by-step explanation:

5 0
2 years ago
A cylindrical tank has a base of diameter 12 ft and height 5 ft. The tank is full of water (of density 62.4 lb/ft3).(a) Write do
saw5 [17]

Answer:

a.  71884.8 π lb/ft-s²∫₀⁵(9 - y)dy

b.  23961.6 π lb/ft-s²∫₀⁵(5 - y)dy

c. 99840π lb/ft-s²∫₀⁶rdr

Step-by-step explanation:

.(a) Write down an integral for the work needed to pump all of the water to a point 4 feet above the tank.

The work done, W = ∫mgdy where m = mass of cylindrical tank = ρA([5 + 4] - y) where ρ = density of water = 62.4 lb/ft³, A = area of base of tank = πd²/4 where d = diameter of tank = 12 ft.( we add height of the tank + the height of point above the tank and subtract it from the vertical point above the base of the tank, y to get 5 + 4 - y) and g = acceleration due to gravity = 32 ft/s²

So,

W = ∫mgdy

W = ∫ρA([5 + 4] - y)gdy

W = ∫ρA(9 - y)gdy

W = ρgA∫(9 - y)dy

W = ρgπd²/4∫(9 - y)dy

we integrate W from  y from 0 to 5 which is the height of the tank

W = ρgπd²/4∫₀⁵(9 - y)dy

substituting the values of the other variables into the equation, we have

W = 62.4 lb/ft³π(12 ft)² (32 ft/s²)/4∫₀⁵(9 - y)dy

W = 71884.8 π lb/ft-s²∫₀⁵(9 - y)dy

.(b) Write down an integral for the fluid force on the side of the tank

Since force, F = ∫PdA where P = pressure = ρgh where h = (5 - y) since we are moving from h = 0 to h = 5. So, P = ρg(5 - y)

The differential area on the side of the tank is given by

dA = 2πrdy

So.  F = ∫PdA

F = ∫ρg(5 - y)2πrdy

Since we are integrating from y = 0 to y = 5, we have our integral as

F = ∫ρg2πr(5 - y)dy

F = ∫ρgπd(5 - y)dy    since d = 2r

substituting the values of the other variables into the equation, we have

F = ∫₀⁵62.4 lb/ft³π(12 ft) × 32 ft/s²(5 - y)dy

F = 23961.6 π lb/ft-s²∫₀⁵(5 - y)dy

.(c) How would your answer to part (a) change if the tank was on its side

The work done, W = ∫mgdr where m = mass of cylindrical tank = ρAh where ρ = density of water = 62.4 lb/ft³, A = curved surface area of cylindrical tank = 2πrh  where r = radius of tank, d = diameter of tank = 12 ft. and h =  height of the tank = 5 ft and g = acceleration due to gravity = 32 ft/s²

So,

W = ∫mgdr

W = ∫ρAhgdr

W = ∫ρ(2πrh)hgdr

W = ∫2ρπrh²gdr

W = 2ρπh²g∫rdr

we integrate from r = 0 to r = d/2 where d = diameter of cylindrical tank = 12 ft/2 = 6 ft

So,

W = 2ρπh²g∫₀⁶rdr

substituting the values of the other variables into the equation, we have

W = 2 × 62.4 lb/ft³π(5 ft)² × 32 ft/s²∫₀⁶rdr

W = 99840π lb/ft-s²∫₀⁶rdr

7 0
3 years ago
18) Solve the system. 0.4x - 0.1y = 2 0.2x + 0.5y = 1 A) (5, 0) B) (0, 5) C) (-5, 0) Eliminate D) (3, -10) please help me its ex
Artemon [7]
To solve the set of equations given above, we can use the substitution method where we substitute one equation to the other and solving for one variable. We do as follows:

<span>0.4x - 0.1y = 2
x = 5 + 0.25y

0.2x + 0.5y = 1
</span>0.2(5 + 0.25y)+ 0.5y = 1
y = 0
x = 5

Therefore, the correct answer from the choices is option A, (5,0).
6 0
2 years ago
Read 2 more answers
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