Answer:
Two real world situations are shown below.
Step-by-step explanation:
Initial population of a certain bacteria is 1 thousand and the population doubles in each hour. So, population of bacteria (in thousands) after x hours is
A person invests 1 lakh rupees in shares and the amount is twice at the end of each year. So, total amount (in lakhs) after x years is
Answer:he must save an average of $150 or more in each of the remaining 8 months.
Step-by-step explanation:
Mr. Helsley wishes to save at least $1500 in 12 months. If he saved $300 during the first 4 months, then the amount left would be
≥ 1500 - 300
Let x represent the least possible average amount that he must save in each of the remaining 8 months. This means that the total amount that he would save in the last 8 months would be 8x. Therefore,
300 + 8x ≥ 1500
8x ≥ 1500 - 300
8x ≥ 1200
x ≥1200/8
x ≥ 150
You should have drawn1 - x-axis and y-axis in light pencil.2 - graphed a down-facing parabola with the top of the frown on the y-axis at y = 2. It should be crossing the x-axis at ±√2. This should be in dark pencil or another color.3 - In dark pencil or a completely new color, draw a rectangle with one of the horizontal sides sitting on top of the x-axis and the other horizontal side touching the parabola at each of the top corners of the rectangle. The rectangle will have half of its base in the positive x-axis and the other half on the negative x-axis. It should be split right down the middle by the y-axis. So each half of the base we will say is "x" units long. So the whole base is 2x units long (the x units to the right of the y-axis, and the x units to the left of the y-axis) I so wish I could draw you this picture... In the vertical direction, both vertical edges are the same length and we will call that y. The area that we want to maximize has a width 2x long, and a height of y tall. So A = 2xy This is the equation we want to maximize (take derivative and set it = 0), we call it the "primary equation", but we need it in one variable. This is where the "secondary equation" comes in. We need to find a way to change the area formula to all x's or all y's. Since it is constrained to having its height limited by the parabola, we could use the fact that y=2 - x2 to make the area formula in only x's. Substitute in place of the "y", "2 - x2" into the area formula. A = 2xy = 2x(2 - x2) then simplify A = 4x - 2x3 NOW you are ready to take the deriv and set it = 0 dA/dx = 4 - 6x2 0 = 4 - 6x2 6x2 = 4 x2 = 4/6 or 2/3 So x = ±√(2/3) Width remember was 2x. So the width is 2[√(2/3)]Height is y which is 2 - x2 = 2 - 2/3 =4/3
Answer:
3.34.
Step-by-step explanation:
4.2 * 0.2 + 2.5
= 0.84 + 2.5
= 3.34.
Answer:
108 cm^2
Step-by-step explanation:
Trapezoid area = (a+b)/2 * h
= (6+12)/2 * 6 = 54 cm^2
Triangle area = b*h/2 = 12* (15-6) / 2 = 54 cm^2
Total area is 54+54 = 108 cm^2
