Answer: (6x^4 - 15x^3 - 2x^2 - 10x - 4) ÷ (3x^2 + 2)
= (6x^4 - 15x^3 + 4x^2 - 6x^2 - 10x - 4) ÷ (3x^2 + 2)
= (6x^4 + 4x^2 - 15x^3 - 10x - 6x^2 - 4) ÷ (3x^2 + 2)
= 2x^2(3x^2 + 2) - 5x(3x^2 + 2) - 2(3x^2 + 2) ÷ (3x^2 + 2)
= (3x^2 + 2)(2x^2 - 5x - 2) ÷ (3x^2 + 2)
= 2x^2 - 5x - 2 Ans.
I hope this helped!!! NO HATE COMMENTS IF I WAS WRONG!!!
1) 3+2+15=20
2) 3/4= 27/36 1/9=4/36
3) 27/36+4/36=31/36
4) 26/27=936/972 31/36= 637/972
5) 936/972 + 637/972= 1573/972= 1 601/972
Correct answer is D).
A) and C) are polynomials, so x∈R, in B) we have √x, and in this case x ≥ 0.
Answer:
I think its A & B
Two Squares with the same side lengths are always congruent and Two rectangles with the same side lengths are always congruent.
Answer:
Step-by-step explanation:
Using the midpoint formula, 
, we can find the coordinates that represents the position of the ship at noon.
Let 
(given on the coordinate plane)
(given also)
Plug in the values into the formula and solve as follows:
Position of the ship at noon is best represented at
