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arlik [135]
3 years ago
7

Larry spends half of his workday teaching piano lessons .if he sees 6 students,each for the same amount of time ,what fraction o

f his workday is spent with each student?

Mathematics
2 answers:
andriy [413]3 years ago
8 0
He spent 1/12 with eaxh student
Galina-37 [17]3 years ago
7 0

Larry spends ¹/₁₂ of his workday with each student

<h3>Further explanation</h3>

Order of Operations in Mathematics follow this following rule :

  • Parentheses
  • Exponents
  • Multiplication and Division
  • Addition and Subtraction

This rule is known as the PEMDAS method.

In working on a mathematical problem, we first calculate operation that is in parentheses, follow by exponentiation, then multiplication or division, and finally addition or subtraction.

Let us tackle the problem!

Let :

<em>Total Time of Larry's Workday = X</em>

<u>Given:</u>

<em>Larry spends half of his workday teaching piano lessons.</em>

\texttt{Duration of Teaching Piano Lessons} = \frac{1}{2} \times \texttt{Total Time of Workday}

\texttt{Duration of Teaching Piano Lessons} = \frac{1}{2} \times X

\texttt{Duration of Teaching Piano Lessons} = \boxed {\frac{1}{2} X}

<em>He sees 6 students , each for the same amount of time.</em>

\texttt{Duration of Teaching Each Student} = \texttt{Duration of Teaching Piano Lessons} \div \texttt{Number of Students}

\texttt{Duration of Teaching Each Student} = \frac{1}{2} X \div 6

\texttt{Duration of Teaching Each Student} = \frac{1}{2} X \times \frac{1}{6}

\texttt{Duration of Teaching Each Student} = \frac{1 \times 1}{2 \times 6} X

\texttt{Duration of Teaching Each Student} = \boxed {\frac{1}{12} X}

<h3>Learn more</h3>
  • Perimeter of Rectangle : brainly.com/question/12826246
  • Elimination Method : brainly.com/question/11233927
  • Sum of The Ages : brainly.com/question/11240586

<h3>Answer details</h3>

Grade: Middle School

Subject: Mathematics

Chapter: Percentage

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point , Multiplication , Division , Exponent , PEMDAS , percentange , percent

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Here is a diagram and its corresponding equation. Find the solution to the equation and explain your reasoning 38 x+7 x+7 x+7 x+
QveST [7]

Answer:

x = (-158)/87

Step-by-step explanation:

Solve for x:

38 x + 7 x + 7 x + 7 x + 7×4 (x + 7) = 38

Hint: | Multiply 7 and 4 together.

7×4 = 28:

38 x + 7 x + 7 x + 7 x + 28 (x + 7) = 38

Hint: | Group like terms in 38 x + 7 x + 7 x + 7 x + 28 (x + 7).

Grouping like terms, 38 x + 7 x + 7 x + 7 x + 28 (x + 7) = 28 (x + 7) + (38 x + 7 x + 7 x + 7 x):

28 (x + 7) + (38 x + 7 x + 7 x + 7 x) = 38

Hint: | Add like terms in 38 x + 7 x + 7 x + 7 x.

38 x + 7 x + 7 x + 7 x = 59 x:

28 (x + 7) + 59 x = 38

Hint: | Distribute 28 over x + 7.

28 (x + 7) = 28 x + 196:

28 x + 196 + 59 x = 38

Hint: | Add like terms in 59 x + 28 x + 196.

28 x + 59 x = 87 x:

87 x + 196 = 38

Hint: | Isolate terms with x to the left hand side.

Subtract 196 from both sides:

87 x + (196 - 196) = 38 - 196

Hint: | Look for the difference of two identical terms.

196 - 196 = 0:

87 x = 38 - 196

Hint: | Evaluate 38 - 196.

38 - 196 = -158:

87 x = -158

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 87 x = -158 by 87:

(87 x)/87 = (-158)/87

Hint: | Any nonzero number divided by itself is one.

87/87 = 1:

Answer: x = (-158)/87

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3 years ago
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Taya2010 [7]

Given:

Seven times the smaller  of two consecutive even  integers  is the same as  -300 minus 4 times the  larger integer.

To find:

The integers .

Solution:

Let the smaller even integer be x.

So, larger even integer is x+2 because they are consecutive even  integers.

Seven times the smaller  integer = 7x

-300 minus 4 times the  larger integer = -300-4(x+2)

Now,

7x=-300-4(x+2)

7x=-300-4x-8

7x+4x=-308

11x=-308

Divide both sides by 11.

x=\dfrac{-308}{11}

x=-28

So, the smaller even integer is -28.

x+2=-28+2=-26

So, the larger even integer is -26.

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Zigmanuir [339]

Answer:

C = 10^y

Step-by-step explanation:

By the definition of a log, C = 10^y

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