7.5minutes/1miles
..............................
3-10 pounds
because it has to be more than 2 pounds and less than 11. hope it helps
Answer:
∠ABC= 45°
Step-by-step explanation:
∠ABC= ∠BCD (alt. ∠s, AB//CD)
(2x +15)°= (3x)°
2x +15= 3x
3x-2x= 15 <em>(</em><em>-2x </em><em>on </em><em>both </em><em>sides)</em>
x= 15
Substituting the value of x:
∠ABC
= ∠BCD
= [3(15)]°
= 45°
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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