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Hatshy [7]
3 years ago
9

Mile markers along the highway tell drivers how many miles they have traveled from one location to another. Suppose Daniel sees

mile marker 141 when he gets onto the highway and mile marker 67 when he exits the highway. How far did Daniel travel on the highway
Mathematics
1 answer:
agasfer [191]3 years ago
3 0
The answer to you question is 74.
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Prove that: –7 is not the arithmetic square root of 49
frez [133]

Answer:

–7 is not the arithmetic square root of 49 only in case we are taking it for natural number.

Step-by-step explanation:

  • The square root of x is that number which on squaring gives the result as x.
  • For example, the square root of 4 is +2 or -2. Because on squaring +2 or -2 we get the number 4.
  • Similarly for the case of 49, the square root might be both +7 or -7.
  • But if we are taking it as a natural number then -7 is not valid. Like for length, quantity or other sort of things -7  is not the arithmetic square root of 49.
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3 years ago
Can a linear function be continuous but not have a domain and range of all real numbers
ivolga24 [154]
"Mathematically yes - but from an engineering point no. And micro black holes are very unstable. They will evaporate extremely violently" hope this helps
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3 years ago
Find the equation of the line that passes through the point (-2,7) and is perpendicular to the line y= 2/5x-1/5
-BARSIC- [3]

Step-by-step explanation:

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3 0
3 years ago
Given that f(x) = x2 + 6x – 2, g(x) = x – 7, and h(x) = x + 4 find each function.
choli [55]

Answer:

A) x² + 7x - 9

Step-by-step explanation:

Deduct\Add each like-term to arrive at your answer.

3 0
4 years ago
Please help
V125BC [204]

A cone that is sliced through the vertex would make the shape of a triangle.

You are told the h eight is 10 cm and the radius is 4 cm.

The radius would be half the base, so the base would be 4 * 2 =8 cm.

The area of the triangle is found by multiplying the base by the height, then dividing by two.

Area = 8 x 10 = 80

80 / 2 = 40 square centimeters.

3 0
3 years ago
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