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lorasvet [3.4K]
3 years ago
7

Help me plss to find the area​

Mathematics
1 answer:
Delvig [45]3 years ago
7 0

Answer:

A=88 square units

Step-by-step explanation:

A=B x H

A= 11 x 8

A=88 square units

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adell [148]
In June he read 0 to 45 pages per day
In April he reads 10 to 90 pages per day
7 0
2 years ago
Today Ian wants to run less than 7/12 mile. Write a fraction with a denominator of 4 to respresent a distance that is less than
Mkey [24]

Lan wants to run less than 7/12 miles. It says to find out a fraction with a denominator of 4 and which is less than 7/12.

Let's assume the required fraction to be x/4 such that x/4 is less than 7/12.

\frac{x}{4} < \frac{7}{12} \\\\ 3*\frac{x}{4} < \frac{7}{12}*3 \\\\ \frac{3x}{4} < \frac{21}{12} \\\\ \frac{3x}{4} < \frac{7}{4} \\\\ 3x < 7

So we must have multiples of 3's that should be less than 7, we have only two choices 3 < 7 or 6 < 7.

It means x = 1 or x = 2, and the required fraction would be 1/4 or 2/4.

2/4 is simplified to 1/2 and the question says to have denominator 4.

Hence, final answer is 1/4

5 0
2 years ago
Solve for f. 2+1.25f=10-2.75f2+1.25f=10−2.75f
Ne4ueva [31]
We have to solve for f:
2 + 1.25 f = 10 - 2.75 f
1.25 f + 2.75 f = 10 + 2
4 f = 12
f = 12 : 4
f = 3
Answer: f = 3
6 0
3 years ago
Please help asap! I will mark brainliest for correct answer!!
solmaris [256]

Answer: Do the math, the positive solution

t = 5.0495 seconds (If it's wrong sorry, I havent done a problem like this one in awhile!)

Step-by-step explanation:

6 0
2 years ago
Assume that the random variable X is normally distributed, with mean 60 and standard deviation 16. Compute the probability P(X &
elixir [45]

Answer:

P(X < 80) = 0.89435.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 60, \sigma = 16

P(X < 80)

This is the pvalue of Z when X = 80. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{80 - 60}{16}

Z = 1.25

Z = 1.25 has a pvalue of 0.89435.

So

P(X < 80) = 0.89435.

5 0
2 years ago
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