Answer:
187.5% increase
Step-by-step explanation:
Percent change formula:
Initially, the program had 8 members and ended with 15 so
Im lost im not sure what to do (Math Problem) plz Help!
1 answer:
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Answer:
(A)Cost of Rental A, C= 15x
Cost of Rental B, C=5x+50
Cost of Rental C, C=9x+20
(B)
i. Rental C ii. Rental A iii. Rental B
Step-by-step explanation:
<u>Part 1</u>
Let x be the number of hours of the barbeque use by the club.
Rental A: $15/h
Cost of Rental A, C= 15hx
Rental B: $5/h + 50
Cost of Rental B, C=5x+50
Rental C: $9/h + 20
Cost of Rental C, C=9x+20
<u>Part 2</u>
The graph of the three models is attached below
<u>Part 3(11.05-4.30)</u>
If the barbecue's usage hour is from 11.05 to 4.30 when the football match ends.
Number of Hours between 11.05am and 4.30pm=4 hours 25 Minutes = 4.42 Hours
Cost of Rental A, C= 15x=15(4.42)=$66.30
Cost of Rental B, C=5x+50 =5(4.42)+50=$72.10
Cost of Rental C, C=9x+20=9(4.42)+20=$59.78
Rental C should be chosen as it offers the lowest cost.
<u>Part 4 (11.05-12.30)</u>
Number of Hours = 12.30 -11.05 =1 hour 25 Minutes = 1.42 Hours
- Cost of Rental A, C= 15x=15(1.42)=$21.30 Cost of Rental B, C=5x+50 =5(4.42)+50=$57.10 Cost of Rental C, C=9x+20=9(4.42)+20=$32.78
Rental A should be chosen since it offers the lowest cost.
<u>Part 5</u>
If the barbecue is returned the next day, say after 24 hours
- Cost of Rental A, C= 15x=15(24)=$360 Cost of Rental B, C=5x+50 =5(24)+50=$170 Cost of Rental C, C=9x+20=9(24)+20=$236
Rental B should be chosen as it offers the lowest cost.
