Answer:
e. the triangles are congruent
Step-by-step explanation:
Similar means they're alike but are not the same, congruent means they're the same. The triangles are the same so therefore they're congruent.
Also it's congruent because u see the triangles on the bottom and top line? It means that the lines are parallel. So the lines at the side have to be the same length and tilt in an equal way so the top and bottom lines can be parallel
Answer:
a) P(a)= 0.0001
b) P(b)= 0.0024
Step-by-step explanation:
Given:
Chosen number = 3079
Possible numbers that have chance of winning from 0000 to 9999= 10,000
Winning condition= if made choice matches the winning digits
Now
a)What is the probability that the winning number matches your number exactly?
From 0000 to 9999, only one time can the number 3079 can be the winning number, so
P(a)= 1/10000
= 0.0001
b)What is the probability that the winning number has the same digits as your number in any order?
Winning numbers from 0000 to 10000 that have same digits as 3079 are
4 x 3 x 2 x 1 = 24 ways
Following are the 24 numbers from 0000 to 9999 that have matching digits to 3079:
0379
0397
0973
0937
0793
0739
3079
3097
3970
3907
3790
3709
7039
7093
7930
7903
7390
7309
9073
9037
9370
9307
9730
9703
P(b)= 24/10000
=0.0024 !
Answer:
<h3>7/10</h3>
Step-by-step explanation:
Using set notation;
Let n(U) be the total number of students in the school = 100%
Let n(M) be the percentage of male students in the school = 56%
Let n(A) be the percentage of students between the ages of 18 and 20 (A) in the school = 32%
Let n(M∩A) be the percentage of both male and between the ages of 18 and 20 = 26%
The n(MUA)' be the number of female students in the school
Using the formula to get n(MUA)
n(MUA) = n(M)+n(A)- n(M∩A)
n(MUA) = 56+32-26
n(MUA) = 62%
Also, n(U) = n(MUA)+n(MUA)'
100 = 62+n(MUA)'
n(MUA)' = 100-62
n(MUA)' = 38%
This means that there are 38% of students in the school.
The probability of choosing a random student who is a female or between the ages of 18 and 20 is expressed as;
P(F or A) = P(F)+P(A) (mutually exclusive event i.e both cannot occur at the same time)
P(F or A) = 38/100 + 32/100
P(F or A) = (38+32)/100
P(F or A) = 70/100
P(F or A) = 7/10
Hence the probability of choosing a random student who is a female or between the ages of 18 and 20 is 7/10.
I need options but so you know which one it is: it is the one with a number followed by an x (or it could just be x)
Hope this helps :)