All categories

2 years ago

I need is the answer of please thank you

Mathematics

2 answers:

MariettaO [177]2 years ago

6 0

Answer:

39.2

Step-by-step explanation:

ok so you are given 2 triangles that are proportional

the 20 m side and the 56 m side go together

so this leaves 14 and L

so the ration is 2.8

multiply 14 by 2.8 and you get 39.2

Savatey [412]2 years ago

4 0

Answer:

39.2m

Step-by-step explanation:

The ratio would be 14/20 which is 0.7. So, you would take 56 and multipy it by 0.7 to get 39.2.

You might be interested in

Relative density was determined for one sample of second-growth Douglas fir 2 x 3 4s with a low percentage of juvenile wood and

Citrus2011 [14]

Answer:

0.03865

Step-by-step explanation:

Since the true density for the two types of trees are given, we would evaluate the average for both of them

Low percentage of juvenile wood density = 0.523 and 0.0543

Average density = 0.523 + 0.0543/2

Average density = 0.55015

Moderate percentage of juvenile wood density = 0.489 and 0.0450

Average density = 0.489 + 0.0450/2

Average density = 0.5115

Therefore, difference in true average density for the two woods are = 0.55015 - 0.51150

= 0.03865

5 0

3 years ago

A line passes through the point (-8, 6) and has a slope of 3/2

Vladimir79 [104]

Answer:

y-6=3/2(x+8)

Step-by-step explanation:

so the point slope form is y-y₁=m(x-x₁)

so enter the points (-8, 6)

y-6= 3/2(x-(-8))

y-6=3/2(x+8)

3 0

3 years ago

Read 2 more answers

F4f fendimulatto juicyminkz

lapo4ka [179]

Answer:

....................

Step-by-step explanation:

7 0

3 years ago

Verify the identity. sin (x+pi/2)=cos x

hram777 [196]

Given data
sin (x+pi/2)=cos x
now using sin law
sin(a+b)=sin(a)cos(b)+cos(a)sin(b)
now using above values
sin(pi/2+x)=sin(pi/2)cos(x)+cos(pi/2)sin(x)
as we know that
sin(pi/2)=1
cos(pi/2)=0
now putting these values
sin(pi/2+x)=1*cosx+0*1
sin(pi/2+x)=cosx
hence proved that

sin (x+pi/2)=cos x

4 0

3 years ago

Two part-time instructors are hired by the Department of Statistics and each is assigned at random to teach a single course in p

scZoUnD [109]

Answer:

The probability that they will teach different courses is $\frac{2}{3}$ .

Step-by-step explanation:

Sample space is a set of all possible outcomes of an experiment.

In this case we will write the sample space in the form (x, y).

Here x represents the course taught by the first part-time instructor and y represents the course taught by the second part-time instructor.

Denote every course by their first letter.

The sample space is as follows:

S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}

The outcomes where the the instructors will teach different courses are:

s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}

The probability of an events E is the ratio of the number of favorable outcomes to the total number of outcomes.

$P(E)=\frac{n(E)}{N}$

Compute the probability that they will teach different courses as follows:

$P(\text{Different courses})=\frac{n(s)}{n(S)}=\frac{6}{9}=\frac{2}{3}$

Thus, the probability that they will teach different courses is $\frac{2}{3}$ .

3 0

3 years ago