Ask question

Ask question

All categories

3 years ago

10

Suppose a charity received a donation of 28.3 million. If this represents 32%of the charity's donated funds, what is the total a

mount of if it's donated funds

1 answer:

guapka [62]3 years ago

8 0

Since the 28.3 represents 32 percent of the whole, you need the other 68%. I'm pretty sure its 88.44.

You might be interested in

What is a probability that rolling a six-sided die results in 2 or 3?

Paraphin [41]

The probability of rolling a 2 would be 1/6

The probability of rolling a 3 would be 1/6

The probability of rolling a 2 or a 3 would be 1/6 + 1/6 = 2/6, which reduces to 1/3

The answer is 1/3

5 0

3 years ago

13. Of 500 athletes surveyed, 300 were male and 20 were left- handed. Only 8 of the left- handed athletes were female. 14. What

Vsevolod [243]

Jupiter Saturn Mars Earth Sun

3 0

2 years ago

Which of the following polynomials is in standard form?

Allushta [10]

Answer:

running a two year contract is the best i have to do with my life in this world and it has a great way to go through the

5 0

3 years ago

Read 2 more answers

Which expression is equivalent to 2*3 / 2^6

Nookie1986 [14]

Answer:

$\frac{3}{32}$

Step-by-step explanation:

$\frac{2*3}{2^6} \\\\\frac{6}{64} \\\\\frac{3}{32}$

6 0

3 years ago

A normal population has a mean of 19 and a standard deviation of 5.

dangina [55]

Answer:

a) $Z = 1.2$

b) 38.49% of the population is between 19 and 25.

c) 34.46% of the population is less than 17.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. If we need to find the probability that the measure is larger than X, it is 1 subtracted by this pvalue.

For this problem, we have that

A normal population has a mean of 19 and a standard deviation of 5, so $\mu = 19, \sigma = 5$ .

(a) Compute the z value associated with 25

This is Z when $X = 25$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{25 - 19}{5}$

$Z = 1.2$

(b) What proportion of the population is between 19 and 25?

This is the pvalue of Z when $X = 25$ subtracted by the pvalue of Z when $X = 19$ .

X = 25 has $Z = 1.2$ , that has a pvalue of 0.8849.

X = 19 has $Z = 0$ , that has a pvalue of 0.5000.

So 0.8849-0.500 = 0.3849 = 38.49% of the population is between 19 and 25.

(c) What proportion of the population is less than 17?

This is the pvalue of Z when $X = 17$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{17 - 19}{5}$

$Z = -0.40$

$Z = -0.40$ has a pvalue of 0.3446.

This means that 34.46% of the population is less than 17.

7 0

3 years ago