Answer:
The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).
Step-by-step explanation:
The final position of the surveyor is represented by the following vectorial sum:
(1)
And this formula is expanded by definition of vectors in rectangular and polar form:
(1b)
Where:
- Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.
- Length of each vector, in kilometers.
- Bearing of each vector in standard position, in sexagesimal degrees.
If we know that
,
,
and
, then the resulting coordinates of the final position of the surveyor is:
![(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})](https://tex.z-dn.net/?f=%28x%2Cy%29%20%3D%20%2842%5C%2Ckm%29%5Ccdot%20%28%5Ccos%2032%5E%7B%5Ccirc%7D%2C%20%5Csin%2032%5E%7B%5Ccirc%7D%29%20%2B%20%2828%5C%2Ckm%29%5Ccdot%20%28%5Ccos%20154%5E%7B%5Ccirc%7D%2C%20%5Csin%20154%5E%7B%5Ccirc%7D%29)
![(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]](https://tex.z-dn.net/?f=%28x%2Cy%29%20%3D%20%2835.618%2C%2022.257%29%20%2B%20%28-25.166%2C%2012.274%29%5C%2C%5Bkm%5D)
![(x,y) = (10.452, 34.531)\,[km]](https://tex.z-dn.net/?f=%28x%2Cy%29%20%3D%20%2810.452%2C%2034.531%29%5C%2C%5Bkm%5D)
According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:
![\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Ctan%5E%7B-1%7D%20%5Cfrac%7B10.452%5C%2Ckm%7D%7B34.531%5C%2Ckm%7D)
![\theta \approx 16.840^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%20%5Capprox%2016.840%5E%7B%5Ccirc%7D)
And the distance from the camp is calculated by the Pythagorean Theorem:
![r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%7B%2810.452%5C%2Ckm%29%5E%7B2%7D%2B%2834.531%5C%2Ckm%29%5E%7B2%7D%7D)
![r = 36.078\,km](https://tex.z-dn.net/?f=r%20%3D%2036.078%5C%2Ckm)
The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).