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tatyana61 [14]
3 years ago
6

Then, the bug ran from −100 to 100. What distance did it cover? If the average speed of the bug during this run was 20 units per

minute, how long did this run take?
Mathematics
1 answer:
asambeis [7]3 years ago
8 0

Answer:

200 units.

10 minutes.

Step-by-step explanation:

Distance = 100 - (-100)

= 100 + 100

= 200 units.

Speed = distance / time

20 = 200/ t

t =  200/20

= 10 minutes.

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H(n)=3n-4 find h(-6)
mrs_skeptik [129]

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3 years ago
Determine the fraction of total interest owed using the rule of 78. After the six month of a 12 month loan, the numerator is: {(
Dima020 [189]

Answer:

The fraction of total interest owed is  \frac{57}{78}

The value of it to the nearest tenth is 73.1%

Step-by-step explanation:

Let us solve it using the rule of 78

∵ The loan = 12 month

∵ The numerator is after 6 month

- Substitute n by 1 in each bracket

∴ The numerator = {(1 + 11) + (1 + 10) + (1 + 9) + (1 + 8) + (1 + 7) + (1 + 6)}

∴ The numerator = {12 + 11 + 10 + 9 + 8 + 7}

∴ The numerator = {57}

∴ The numerator of the fraction is 57

∵ The denominator = {(n) + (n + 1) + (n + 2) + .......... + (n + 11)}

- substitute n by 1 in each bracket

∴ The denominator = {1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12}

∴ The denominator = {78}

∴ The denominator of the fraction is 78

The fraction of total interest owed is  \frac{57}{78}

Now find the value of the fraction

∵ The fraction = \frac{57}{78}

∴ Its value = 0.7307692308 × 100%

∴ Its value = 73.07692308%

- Round it to the nearest tenth

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The value of it to the nearest tenth is 73.1%

5 0
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96/120 as a percentage
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Step-by-step explanation:

Mean temperatue (μ) = 1000°F

Standard Deviation (σ) = 50 °F

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P(X

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