Question

The stockroom has provided you with a 1.70 MM stock solution of NaCl NaCl. What volume of this stock solution would be required to prepare 230 mLmL of a 0.170 M NaCl NaCl solution

Answer 1

Answer: The volume of stock NaCl solution needed is 23 mL

Explanation:

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the stock NaCl solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted NaCl solution

We are given:

$M_1=1.70M\\V_1=?mL\\M_2=0.170M\\V_2=230mL$

Putting values in above equation, we get:

$1.70\times V_1=0.170\times 230\\\\V_1=\frac{0.170\times 230}{1.70}=23mL$

Hence, the volume of stock NaCl solution needed is 23 mL