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umka2103 [35]
3 years ago
14

CalcuLate the velocity of an electron ejected if 300.0 mm of light is applied to the surface. A wavelength of 795 nm has suffici

ent energy to eject electrons.
Chemistry
1 answer:
worty [1.4K]3 years ago
8 0
The equation relating velocity and wavelength is written below:

v = λf
where λ is the wavelength in m while f is frequency in 1/s.

Let's determine first the frequency from the speed of light:
c = distance/time, where c is the speed of light equal to 3×10⁸ m/s
3×10⁸ m/s = (300 mm)(1 m/1000 mm)/ time
time = 1×10⁻⁹ seconds
Since f = 1/t,
f = 1/1×10⁻⁹ seconds = 10⁹ s⁻¹

Thus,
v = (795×10⁻⁹ m)(10⁹ s⁻¹)
v = 795 m/s
You might be interested in
Dr. Patel and her team have been using GPS to track two plates that are moving toward each
Andru [333]

C: One plate is going underneath the other plate and sinking into the soft rock below.

Explanation:

Where plates are moving towards each other they are said to converging, and are called convergent margins.

The lithosphere is broken into series of slabs called plates. The plates moves on the weak and relatively soft asthenosphere below.

Plates have different motion. At some places, they move apart and they are said to be divergent.

When plates moves towards each other, they are convergent. At a convergent margin, a plate collides with another thereby causing the denser plate usually the oceanic plate to subduct into the asthenosphere. In some other cases, the plates can collide and build upward.

Learn more:

Lithosphere brainly.com/question/9582362

#learnwithBrainly

7 0
3 years ago
Approximately how many moles of chlorine make up 1.79 × 1023 atoms of chlorine?
e-lub [12.9K]
1.2*10^24# atoms of chlorine

Explanation:
Chlorine gas (#Cl_2#) has two atoms of elemental chlorine in a molecule, so:
#1# mol of #Cl_2# have #6*10^23# molecules of #Cl_2#
#1# molecule of #Cl_2# have #2# atoms per molucule
Then #2*6*10^23 = 1.2*10^24# atoms of chlorine in a mol of chlorine gas
6 0
3 years ago
When the following aqueous solutions are mixed together, a precipitate forms. Balance the net ionic equation in standard form fo
rewona [7]

<u>Answer:</u>

<u>For (a):</u> The balanced net ionic equation is 2Ag^{+}(aq)+S^{2-}(aq)\rightarrow Ag_2S(s) and the sum of coefficients is 4

<u>For (b):</u> The balanced net ionic equation is Pb^{2+}(aq)+2Cl^{-}(aq)\rightarrow PbCl_2(s) and the sum of coefficients is 4

<u>For (c):</u> The balanced net ionic equation is Ca^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CaCO_3(s) and the sum of coefficients is

<u>For (d):</u> The balanced net ionic equation is Ba^{2+}(aq)+2OH^{-}(aq)\rightarrow Ba(OH)_2(s) and the sum of coefficients is 4

<u>For (e):</u> The balanced net ionic equation is Ag^{+}(aq)+Cl^{-}(aq)\rightarrow AgCl(s) and the sum of coefficients is 3

<u>Explanation:</u>

Net ionic equation is defined as the equations in which spectator ions are not included.

Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.

  • For (a): Sodium sulfide and silver nitrate

The balanced molecular equation is:

Na_2S(aq)+2AgNO_3(aq)\rightarrow 2NaNO_3(aq)+Ag_2S(s)

The complete ionic equation follows:

2Na^{+}(aq)+S^{2-}(aq)+2Ag^+(aq)+2NO_3^{-}(aq)\rightarrow 2Na^+(aq)+2NO_3^-(aq)+Ag_2S(s)

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

2Ag^{+}(aq)+S^{2-}(aq)\rightarrow Ag_2S(s)

Sum of the coefficients = [2 + 1 + 1] = 4

  • For (b): Lead(II) nitrate and sodium chloride

The balanced molecular equation is:

2NaCl(aq)+Pb(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+PbCl_2(s)

The complete ionic equation follows:

2Na^{+}(aq)+2Cl^{-}(aq)+Pb^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^+(aq)+2NO_3^-(aq)+PbCl_2(s)

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

Pb^{2+}(aq)+2Cl^{-}(aq)\rightarrow PbCl_2(s)

Sum of the coefficients = [2 + 1 + 1] = 4

  • For (c): Calcium nitrate and potassium carbonate

The balanced molecular equation is:

K_2CO_3(aq)+Ca(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+CaCO_3(s)

The complete ionic equation follows:

2K^{+}(aq)+CO_3^{2-}(aq)+Ca^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2K^+(aq)+2NO_3^-(aq)+CaCO_3(s)

As potassium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

Ca^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CaCO_3(s)

Sum of the coefficients = [1 + 1 + 1] = 3

  • For (d): Barium nitrate and sodium hydroxide

The balanced molecular equation is:

2NaOH(aq)+Ba(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+Ba(OH)_2(s)

The complete ionic equation follows:

2Na^{+}(aq)+2OH^{-}(aq)+Ba^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^+(aq)+2NO_3^-(aq)+Ba(OH)_2(s)

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions

The net ionic equation follows:

Ba^{2+}(aq)+2OH^{-}(aq)\rightarrow Ba(OH)_2(s)

Sum of the coefficients = [2 + 1 + 1] = 4

  • For (e): Silver nitrate and sodium chloride

The balanced molecular equation is:

NaCl(aq)+AgNO_3(aq)\rightarrow NaNO_3(aq)+AgCl(s)

The complete ionic equation follows:

Na^{+}(aq)+Cl^{-}(aq)+Ag^{+}(aq)+NO_3^{-}(aq)\rightarrow Na^+(aq)+NO_3^-(aq)+AgCl(s)

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

Ag^{+}(aq)+Cl^{-}(aq)\rightarrow AgCl(s)

Sum of the coefficients = [1 + 1 + 1] = 3

8 0
3 years ago
When chemists convert ethene (C2H2) to ethanol (CH3CH2OH), they have a mixture of the two gaseous substances. Why do chemists th
emmainna [20.7K]

Answer:

to collect liquid ethanol and leave ethene as a gas because ethanol has hydrogen bonds    

Explanation:

The chemist would be lesser than the temperature of the mixture as to collect the liquid ethanol and then leave ethene as a gas since the ethanol is a bond that should be hydrogen. Also -OH that available in the ethanol would be responsible for the hydrogen bonds also it is the main and significant molecular forice

So as per the given situation the above represent the answer

3 0
3 years ago
10. How many g of Cu(OH)2 can be made from 9.1 x 1025 atoms of O?
il63 [147K]
Molar mass Cu(OH)₂ = 97.561 g/mol

97.561 g Cu(OH)₂ --------------- 6.02x10²³ atoms
  ? g Cu(OH)₂ -------------------- 9.1x10²⁵ atoms

mass = 9.1x10²⁵ * 97.561 / 6.02x10²³

mass = 8.87x10²⁷ / 6.02x10²³

mass = 14734.2 g

hope this helps!
8 0
3 years ago
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