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3 years ago

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Oct 15, 9:09:45 AM

1 answer:

Alina [70]3 years ago

5 0

I believe angle ZB would be 138 degrees
(Apologies if I am wrong)

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PLEASE ANSWER FAST 11 POINTS TO WHOEVER DOES WILL GET BRAIN LISTED PLEASE ANSWER I NEED THIS ASAP

dmitriy555 [2]

Answer: Yes, Raoul is correct because the initial value, also known as the y-intercept of function A is 0 and function B is 3.

Step-by-step explanation: The initial value is when x=0.

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2 years ago

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An $8 item is marked up 75%. What is the cost of the item?

UNO [17]

14 dollars because it’s only 75 % out of. 8

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2 years ago

Solve the inequality 13 > 3x + 1

Ivenika [448]

4 > x

step by step explanation:

13 > 3x + 1
-1 -1
12 > 3x
/3 /3
4 > x

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2 years ago

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The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\$

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305$

The degrees of freedom for this sample size are:

$df=n-1=50-1=49$

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=2.01 \cdot 0.305=0.61$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95$

The 95% confidence interval for the mean is (5.73, 6.95).

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3 years ago

Choose Yes or No to tell if the fraction 58 will make each equation true.

loris [4]

No it doesn’t make any of them true

5 0

3 years ago

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