Answer:
Explanation:
A woman with type A blood (whose father was type O) meaning her genotype is AO mates with
Man that has type O blood (OO genotype)
Both are heterozygous for MN blood group and both also heterozygous for the FUT1 gene controlling the synthesis of the H substance (Hh)- which determines the expression of the A and B antigen.
Cross
A O M N H h
O AO OO M MM MN H HH Hh
O AO OO N MN NN h Hh hh
Type A- 1/2 O-1/2 type M- 1/4 MN-1/2 N- 1/4, type H- 3/4 h-1/4
Type A with M antigen:
1/2*1/4*3/4 = 3/32
Type A with M and N antigens:
1/2*1/2*3/4 = 3/16
Type A with N antigen:
1/2*1/4*3/4 = 3/32
Type O with M antigen:
1/2*1/4*3/4= 3/32
Type O with M and N antigens:
1/2*1/2*3/4 = 3/16
Type O with N antigen:
1/2*1/4*3/4 = 3/32.
The 3/4 value comes from the expression of Hh-3/4 (this determines if the A and B Angie will be expressed).
That statement would be True
Answer:
A: dedrite
B: cell body
c: axon terminal
d: axon
e: nucleus
Explanation:
I got the question right.
Please give me brainliest.
The answer is C. If you want a good experiment on this place an egg in a glass of vinegar for 6 hours, remove and place into corn syrup for 6 hours, and finally remove and place into water for 6 hours. you’ll get a really good example of osmosis in different stages.
<span>The ratio of both groups would stay the same. Reason being the ratio in urine osmolality is divided by blood osmolality. The mice with no access to water the ratio of urine osmolality to blood osmolality are 14:7 while for mice with unlimited access to water the ratio of urine osmolality to blood osmolality is 1:4. In conclusion, the mice with no access to water produce highly concentrated urine.</span>
