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Ksju [112]
4 years ago
15

Solve 5 over x minus 5 equals the quantity of x over x minus 5, minus five fourths for x and determine if the solution is extran

eous or not
Mathematics
2 answers:
Soloha48 [4]4 years ago
8 0
5/(x-5)=x/(x-5)-5/4.
Multiply through by 4(x-5):
20=4x-5(x-5).
20=4x-5x+25=25-x, x=5.
This is an extraneous solution because when x=5, the denominators become zero so division by zero occurs, and the result is meaningless.
Natalija [7]4 years ago
8 0
ANSWER

The solution
x = 5
is extraneous.

EXPLANATION

The given equation is

\frac{5}{x - 5}  =  \frac{x}{x - 5} -  \frac{5}{4}

We multiply the above equation with the least common multiple of denominators which is
4(x - 5)


This implies that,

4(x - 5) \times \frac{5}{x - 5}  = 4(x - 5) \times  \frac{x}{x - 5} -  \frac{5}{4}   \times 4(x - 5)



This simplifies to

20  = 4x-  5x + 25

20 - 25 = 4x - 5x


This implies that,


- 5 =  - x



Therefore
x = 5


But this solution does not satisfy the original equation.



\frac{5}{5 - 5}   \ne  \frac{5}{5 - 5} -  \frac{5}{4}


\frac{5}{0}   \ne  \frac{5}{0} -  \frac{5}{4}


Hence
x = 5
is an extraneous solution.
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