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Anastaziya [24]
3 years ago
11

What is the adjective in these sentence the elephant had a long twisty trunk.which of the word is adjective .

Mathematics
1 answer:
Zanzabum3 years ago
5 0
“Long” and “ twisty”
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Which ordered pair is the solution to the system of equations?
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Simplify | (27x – 45) - (4x – 9).<br> Write your answer in factored form.<br> HELP MEEEEEEEE
oksian1 [2.3K]

Answer:

Step-by-step explanation:

27x - 45 - 4x + 9

23x - 36

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3 years ago
What is the value of x
miss Akunina [59]
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Initially a tank contains 10 liters of pure water. Brine of unknown (but constant) concentration of salt is flowing in at 1 lite
zhenek [66]

Answer:

Therefore the concentration of salt in the incoming brine is 1.73 g/L.

Step-by-step explanation:

Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.

Let the concentration of salt  be a gram/L

Let the amount salt in the tank at any time t be Q(t).

\frac{dQ}{dt} =\textrm {incoming rate - outgoing rate}

Incoming rate = (a g/L)×(1 L/min)

                       =a g/min

The concentration of salt in the tank at any time t is = \frac{Q(t)}{10}  g/L

Outgoing rate = (\frac{Q(t)}{10} g/L)(1 L/ min) \frac{Q(t)}{10} g/min

\frac{dQ}{dt} = a- \frac{Q(t)}{10}

\Rightarrow \frac{dQ}{10a-Q(t)} =\frac{1}{10} dt

Integrating both sides

\Rightarrow \int \frac{dQ}{10a-Q(t)} =\int\frac{1}{10} dt

\Rightarrow -log|10a-Q(t)|=\frac{1}{10} t +c        [ where c arbitrary constant]

Initial condition when t= 20 , Q(t)= 15 gram

\Rightarrow -log|10a-15|=\frac{1}{10}\times 20 +c

\Rightarrow -log|10a-15|-2=c

Therefore ,

-log|10a-Q(t)|=\frac{1}{10} t -log|10a-15|-2 .......(1)

In the starting time t=0 and Q(t)=0

Putting t=0 and Q(t)=0  in equation (1) we get

- log|10a|= -log|10a-15| -2

\Rightarrow- log|10a|+log|10a-15|= -2

\Rightarrow log|\frac{10a-15}{10a}|= -2

\Rightarrow |\frac{10a-15}{10a}|=e ^{-2}

\Rightarrow 1-\frac{15}{10a} =e^{-2}

\Rightarrow \frac{15}{10a} =1-e^{-2}

\Rightarrow \frac{3}{2a} =1-e^{-2}

\Rightarrow2a= \frac{3}{1-e^{-2}}

\Rightarrow a = 1.73

Therefore the concentration of salt in the incoming brine is 1.73 g/L

8 0
3 years ago
If equal amounts are added to the numerator and the denominator of the current ratio, the ratio will always:
Marta_Voda [28]

Answer:

Increase?

Step-by-step explanation:

Because think about it let's use 1/2 as an example.

1/2 equals .5 now lets add 2 to both the numerator and denominator

3/4 is the result and it also equals .75 which is larger than .5 so that's why the answer is increase.

and u can keep on going on with the method

4/5=.8

7 0
3 years ago
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