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Misha Larkins [42]
3 years ago
10

Find the remainder when f(x) is divided by (x - k). f(x) = 4x3 - 6x2 + 3x + 1; k= -2

Mathematics
2 answers:
laila [671]3 years ago
8 0
\frac{f(x)}{(x-k)}
\frac{4x^3-6x^2+3x+1}{(x+2)}
Using Long Division, pic below
Your remainder is -61

WITCHER [35]3 years ago
5 0
When f(x) is divided by (x - k). f(x) = 4x3 - 6x2 + 3x + 1; k= -2     f(x)______    when f(x) is divided by (x - k). f(x) = 4x3 - 6x2 + 3x + 1; k= -2     i-k     
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B) g(-1)
Dahasolnce [82]

Answer:

just sub in the numbers into the equation to replace the X ..

example for

a) h(7) : 44

Step-by-step explanation:

h(7) : x^2 -5

sub in 7 into the equation to replace X

so you get

(7)^2 - 5

49-5

44

4 0
3 years ago
Find the measure of the missing angles.<br> 62°<br> b\co
tiny-mole [99]

The measures of angles B and C are 118° and 62°, respectively.

<h3>What are the measures of two missing angles generated by the intersection of two lines?</h3>

A system of three angles is generated by two lines intersecting each other. In accordance with Euclidean geometry, angle C is opposite to the angle with measure 62° and angle B is supplementary to the same angle.

When two angles are opposite, then both have the same measure, and when two angles are supplementary, then the sum of their measures equals 180°. Therefore, the measures of angles B and C are 118° and 62°, respectively.

To learn more on angles: brainly.com/question/7116550

#SPJ1

8 0
2 years ago
Determine whether the following conjecture is true or false. Give a counterexample if the answer is false.
brilliants [131]
This conjecture is false, A and C don't have to be complementary angles.

Let Angle A be 100 and Angle B be 80 degrees. They are supplementary (sum of 180).
Let Angle C be 100 and Angle B is still 80 degrees. They are supplementary.

However, Angle A and Angle C are not complementary (sum of 90).
4 0
3 years ago
The endpoints of a line segment graphed on a Cartesian coordinate system are (4, 1) and (-2, -4). What are the coordinates of th
Masja [62]
The midpoint of (x1,y1) and (x2,y2) is (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

just average them


(4,1) and (-2,4)
the midpoint is  (\frac{4-2}{2},\frac{1-4}{2})=(\frac{2}{2},\frac{-3}{2})=(1,-1.5)
5 0
3 years ago
Read 2 more answers
Solve the inequality<br> 7x&lt;5x-8
Aleksandr [31]
Minust 5x both sides
7x-5x<5x-5x-8
2x<-8
divide by 2 both sides
x<-4
6 0
3 years ago
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