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Misha Larkins [42]
3 years ago
10

Find the remainder when f(x) is divided by (x - k). f(x) = 4x3 - 6x2 + 3x + 1; k= -2

Mathematics
2 answers:
laila [671]3 years ago
8 0
\frac{f(x)}{(x-k)}
\frac{4x^3-6x^2+3x+1}{(x+2)}
Using Long Division, pic below
Your remainder is -61

WITCHER [35]3 years ago
5 0
When f(x) is divided by (x - k). f(x) = 4x3 - 6x2 + 3x + 1; k= -2     f(x)______    when f(x) is divided by (x - k). f(x) = 4x3 - 6x2 + 3x + 1; k= -2     i-k     
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Are these ratios equivalent?
Debora [2.8K]
<h3>Answer:  Yes</h3>

========================================================

Explanation

The ratio 8:10 simplifies to 4:5 when you divide both parts by 2.

The ratio 16:20 simplifies to 4:5 when you divide both parts by 4

Therefore the two ratios 8:10 and 16:20 are both equal 4:5, so they are equal to one another.

------------

Put another way,

(8 large)/(10 small) = (16 large)/(20 small)

8/10 = 16/20

8*20 = 10*16 ... cross multiply

160 = 160

We get a true equation, so the first equation is true as well.

This shows the ratios are equivalent.

-------------

Or you could have...

(8 large)/(16 large) = (10 small)/(20 small)

8/16 = 10/20

8*20 = 16*10

160 = 160

We get the same conclusion as before.

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Step-by-step explanation:

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