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3 years ago

Given the following functions f(x) and g(x), solve f[g(6)]. f(x) = 6x + 12 g(x) = x − 8

Mathematics

2 answers:

iogann1982 [59]3 years ago

6 0

Answer:

Answer:

Option 2nd is correct.

=0.

Step-by-step explanation:

Given the function:

Solve:

First calculate:

f[g(x)]

Substitute the function g(x)

Replace x with x-8 in the function f(x) we get;

The distributive property says that:

Using distributive property:

⇒

Put x = 6 we get;

Therefore, the value of is 0.

Step-by-step explanation:

dalvyx [7]3 years ago

5 0

Answer:

Step-by-step explanation:

f(x) = 6x + 12

g(x) = x − 8

f(g(6))=?

g(6)=6-8= -2

f(-2)= -2*6+12= -12+12=0

f(g(6))= f(-2)=0

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3 years ago

Justin has $7.50 more than Eva, and Emma has $12 less than Justin. Together, they have a total of $63.00. How much money does ea

uysha [10]

Answer:

Step-by-step explanation: emma's amount be X . justin has $7.50+x because he has $7.50 more than emma.Since emma has 7.50+x-$12.to get everyones amount add what they have together which is=$7.50+x+$7.50+x-12 which in total is $63.00.after the calculations you get x=30.now distribute the x equally. so justin has $7.50+30=37.50.we also distribute it with emma's which is 7.50+30-12=25.5.

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5 0

3 years ago

Factorise fully x^3-x

MA_775_DIABLO [31]

Answer:

$x(x+1)(x-1)$

Step-by-step explanation:

We see that the two terms share an x, so we can pull that out:

$x^3-x=x(x^2-1)$

Now notice that we have a difference of squares ( $x^2-1$ ). Given a difference of squares, $a^2-b^2$ , this can always be factored into $(a+b)(a-b)$ . We can use this in this case: $x^2-1=(x+1)(x-1)$ .