All categories

2 years ago

Find three consecutive integers such that that product of the first and third is one

Mathematics

1 answer:

Tema [17]2 years ago

7 0

Answer:

n = the first

n + 1 = the 2nd

n + 2 = the 3rd

n(n + 2) - (n + 1) = 10(n + 2) + 1

n2 + 2n - n - 1 = 10n + 20 + 1

n2 - 9n - 22 = 0

(n - 11)(n + 2) = 0

If two factors = 0, at least one must = 0.

n - 11 = 0

n = 11

11,12,13

n + 2 = 0

n = -2

-2,-1,0

You might be interested in

Right answers only will give brainliest!!!

vladimir2022 [97]

Answer:

10.7 cm^2

Step-by-step explanation:

First find the area of the base

A = 1/2 *2*1.7

A =1.7

Then find the area of one of the sides

A = 1/2 (2*3)

A = 3

There are 3 sides and they are identical

Multiply one of the sides by 3

3*3=9

Add the sides and the base together

9+1.7

10.7 cm^2

4 0

3 years ago

Read 2 more answers

If f(x) = (2x^3 − 4)^6, then what is f '(x)?

Dominik [7]

The correct answer is:

6(2x^3-4)^5(6x^2)

Explanation:

That is the derivative after you differentiate using the Chain Rule.

4 0

2 years ago

13u - v + 8 Coefficients.

Aleks04 [339]

Answer:

the coefficient in the equation is 13

Step-by-step explanation:

a coefficient is a number that is in front of a variable. 13 is in front of the variable u so it is the coefficient.

6 0

3 years ago

Read 2 more answers

i am using my big brothers acount. i need help johnny got 10 apples and he had 10 dollars now he dosent have money. did he spend

Oxana [17]

Answer:

Yes. He spent 10 dollars.

Step-by-step explanation:

If he bought 10 apples, and he had 10 dollars, he would have no money left because each apple was 1 dollar.

hope this helps!

4 0

2 years ago

If Ben invests $4500 at 4% interest per year, how much additional money must he invest at 5 1/2% annual interest to ensure that

pogonyaev

$Step \; 1: \; Assing \; variable \; for \; the \; unknown \; that \; we \; need \; to \; find.\\Let \; x \; be \; additional \; money \; invested$

$Step \; 2: \; Use \; the \; appropriate \; formula \; of \; simple \; interest \; set \; up \; an \; equation\\Interest \; earned \; each \; year = \; Amount \; invested \times annual \; rate \; of \; interest\\\\Amount \; invested \; in \; 4 \% \; rate \; of \; interest=\$4500\\Amount \; invested \; in \; 5\frac{1}{2}\% \; rate \; of \; interest= \$x\\Amount \; invested \; totally \; in \; 4\frac{1}{2}\% \; rate \; of \; interest = \$(4500+x)$

$Interest \; earned \; in \; 4\% \; interest \; rate\\ = \; 4500(4\%)=180\\Interest \; earned \; in \; 5\frac{1}{2}\% \; interest \; rate\\ = x(5\frac{1}{2}\%)=0.055x\\Interest \; earned \; totally \; in \; 4\frac{1}{2}\% \; interest \; rate = (4500+x)(4\frac{1}{2}\%)\\=0.045(4500+x)$

$\\\\So, \; the \; equation \; would \; be:\\180+0.055x=0.045(4500+x)$

$Step \; 1: \; Distribute \; 0.045 \; in \; the \; right \; side\\180+0.055x=202.5+0.045x\\\\Step \; 2: \; Subtract \; 0.045x \; and \; 180 \; on \; both \; sides \; to \; get \; x \; alone\\0.055x-0.045x=202.5-180\\\\Step \; 3: \; Combine \; Like \; Terms\\0.01x=22.5\\\\Step \; 4: Divide \; 0.01 \; on \; both \; sides\\\frac{0.01x}{0.01}=\frac{22.5}{0.01}\\\\Step \; 5: \; Simplifying \; fraction \; on \; both \; sides\\x=2250$

$\underline{Conclusion:}\\Ben \; should \; invest \; additional \; money \; of \; \$2250$

5 0

3 years ago