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Inga [223]
2 years ago
6

Find three consecutive integers such that that product of the first and third is one

Mathematics
1 answer:
Tema [17]2 years ago
7 0

Answer:

n = the first

n + 1 = the 2nd

n + 2 = the 3rd

n(n + 2) - (n + 1) = 10(n + 2) + 1

n2 + 2n - n - 1 = 10n + 20 + 1

n2 - 9n - 22 = 0

(n - 11)(n + 2) = 0

If two factors = 0, at least one must = 0.

n - 11 = 0

n = 11

11,12,13

n + 2 = 0

n = -2

-2,-1,0

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Answer/Step-by-step explanation:

An equation that describes the relationship can be written as y = mx.

Using the two sets of coordinates, (2, 140) and (4, 280), calculate the slope (m) as shown below:

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Step-by-step explanation:

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Answer:

\mathrm{C)\:}x=15,\:-7

Step-by-step explanation:

For |a-b|=c, there are two possible cases:

\begin{cases}a-b=c\\a-b=-c\\\end{cases}

Solving for both cases, we get:

\begin{cases}x-4+6=17, \:x+2=17, \: \fbox{$x=15$}\\-(x-4)+6=17,\: -x+10=17, \: -x=7, \:, \fbox{$x=-7$}\\\end{cases}

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$11.00

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8 0
3 years ago
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