Question

If -nx^3 + tx + c = 0, what is x equal to?Never mind, found it. 

Answer 1

$-nx^3 + tx + c = 0\ /:(-n)\ \ \ \wedge\ \ \ n \neq 0\\ \\x^3- \frac{t}{n} x-\frac{c}{n}=0\\ \\\Delta=(- \frac{t}{n})^3+(-\frac{c}{n})^2= \frac{-t^3}{n^3} + \frac{c^2}{n^2} = \frac{-t^3+n\cdot c^2}{n^3} \\ \\\Delta>0\ \ \Rightarrow\ \ \ x= \sqrt[3]{ \frac{c}{2n}- \sqrt\Delta} } +\sqrt[3]{ \frac{c}{2n}+ \sqrt\Delta} \\ \\\Delta=0\ \ \ \Rightarrow\ \ \ x_1=\sqrt[3]{ \frac{c}{2n}},\ \ \ \ x_2=-2\sqrt[3]{ \frac{c}{2n}}\\ \\\Delta$