The original price for one lunch special is $19.
<em><u>Explanation</u></em>
The original price for one lunch special is 'p' dollar.
He wins a coupon for $4 off for each of five days. That means , <u>he needs to pay 
dollar each day</u>.
So, the total amount needed to pay for 5 days 
dollar
Given that, <u>he pays $75 for his 5 lunch specials</u>. So the equation will be.....
So, the original price for one lunch special is $19.
Answer:
2550
Step-by-step explanation:
Hope This Helps
Variable: a symbol for a number you don’t know yet
inequality: 60=22+8x
Solution:
<u>Given:</u>
<u>Solve the equation by isolating the variable.</u>
- => 18 = 2b
- => 2b/2 = 18/2
- => b = 9
The value of b is 9.
Hoped this helped!
Answer:
325
Step-by-step explanation:
Total Tickets = 585
Let the adult tickets be = x
If 65 fewer student tickets were sold than adult tickets then Student tickets = x-65
Student Tickets + Adult Tickets = 585
x + (x-65) = 585
x + x - 65 = 585
2x - 65 = 585
2x = 585 + 65
2x = 650
2x/2 = 650/2
x = 325
Answered by Gauthmath
