Do you want a general solution or from 0 <= x < 2pi?
tan^2(2x) - 1 = 0
tan^2(2x) = 1
Take the square root of both sides,
tan(2x) = +/- 1
Two equations:
tan(2x) = 1
tan(2x) = -1
Solve each equation.
tan(2x) = 1, 2x = {pi/4, 5pi/4, 9pi/4, 13pi/4},
x = { pi/8, 5pi/8, 9pi/8, 13pi/8 }
tan(2x) = -1, 2x = { 3pi/4, 7pi/4, 11pi/4, 15pi/4 },
x = { 3pi/8, 7pi/8, 11pi/8, 15pi/8}
So for solutions within [0, 2pi),
x = {pi/8, 3pi/8, 5pi/8, 7pi/8, 9pi/8, 11pi/8, 13pi/8, 15pi/8 }
Answer:

Step-by-step explanation:
The following piecewise functions are linear functions. The graph of any of them is a line segment.
We just need to calculate the value of the function at each end specified in the brace.

Substitute x =-1 and x = 0:

Range of this piece is [-5; -2)

Substitute x =0and x = 5:

Range of this piece is [3; 13)
Therefore the range of the following piecewise function is:

Look at the picture.
Answer: Hello, The number would be 20
Step-by-step explanation: Hope this helps :) tell me if wrong :(
Answer:
2
Step-by-step explanation:
20-7x=6x-6
20+6=6x+7x
26=13x
x=2
Answer:
t= 0
Step-by-step explanation:
Using the rules of logarithms
log x + log y = log(xy)
1 = 0
Given
a +
= t ,then
(a ×
) = t
1 = t , thus
t = 0