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2 years ago

How would a one-fifth in numbers be?

Mathematics

1 answer:

Crazy boy [7]2 years ago

8 0

It’s in many different forms:20 or .20 or 20%

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Which is the best approximation for the solution of the system of equations? y = x + 1 y = 3x – 2

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B. (0.88,0.65) would be the closest approximation for this system of these choices.

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2 years ago

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Calculate the slant height for the given square pyramid. Round to the nearest tenth.

spayn [35]

the answer would have to be 7.8

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2 years ago

Consider the figure shown below. Find the value of BL

Gnesinka [82]

Answer:

BL = 2

Step-by-step explanation:

Given:

AL = 3

AC = 10

BC = 9

AL = AM = 3 (tangents drawn form am external point)

CM = AC - AM

CM = 10 - 3

CM = 7

CM = CN = 7 (tangents drawn form am external point)

BN = BC - CN

BN = 9 - 7

BN = 2

BN = BL = 2 (tangents drawn form am external point).

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2 years ago

True or false: 4/8 and 10/16 are equivalent fractions?

lorasvet [3.4K]

Answer:

False

Step-by-step explanation:

Multiply 8 by 2 to create the common denominator (which is 16).

Now multiply 4 by 2 to keep the fraction even.

This gives you the fraction 8/16 which is not equivalent to 10/16.

Another way you could write this inequality:

8/16 < 10/16

4 0

2 years ago

Rewrite the statement in mathematical notation. (Let y be the distance from the top of the ladder to the floor, x be the distanc

In-s [12.5K]

Answer:

$\frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}$

Step-by-step explanation:

Let L be the length of the ladder,

Given,

x = the distance from the base of the ladder to the wall, and t be time.

y = distance from the base of the ladder to the wall,

So, by the Pythagoras theorem,

$L^2 = y^2 + x^2$

$\implies L = \sqrt{y^2 + x^2}$ ,

Differentiating with respect to time (t),

$\frac{dL}{dt}=\frac{d}{dt}(\sqrt{x^2 + y^2})$

$=\frac{1}{2\sqrt{x^2 + y^2}}\frac{d}{dt}(x^2 + y^2)$

$=\frac{1}{2\sqrt{x^2 + y^2}}(2x\frac{dx}{dt}+2y\frac{dy}{dt})$

$=\frac{1}{\sqrt{x^2 +y^2}}(x\frac{dx}{dt}+y\frac{dy}{dt})$

Here,

$\frac{dy}{dt}=-6\text{ ft per sec}$

Also, $\frac{dL}{dt} = 0$ ( Ladder length = constant ),

$\implies \frac{1}{\sqrt{x^2 +y^2}}(x(-6)+y\frac{dy}{dt})=0$

$-6x + y\frac{dy}{dt}=0$

$y\frac{dy}{dt}=6x$

$\implies \frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}$

Which is the required notation.

8 0

2 years ago

How would a one-fifth in numbers be?​

How would a one-fifth in numbers be?