Answer:
g(x) = x+1
Step-by-step explanation:
Informally, you can see that the function h(x) takes the root of a value that is 1 more than the value under the same radical in f(x). This suggests that adding 1 to x in f(x) will give you h(x). That is, ...
h(x) = f(x+1) = f(g(x))
so
g(x) = x+1
_____
More formally, you can apply the inverse of the function f(x) to the equation ...
h(x) = f(g(x))
f^-1(h(x)) = f^-1(f(g(x))) . . . inverse function applied
f^-1(h(x)) = g(x) . . . . . . . . . simplified
Now f^-1(x) can be found by solving for y in ...
x = f(y)
x = ∛(y+2) . . . . . . . . . definition of f(y)
x^3 = y+2 . . . . . . . . . cube both sides
x^3 -2 = y = f^-1(x) . . . subtract 2 from both sides
So, f^-1(h(x)) is ...
f^-1(h(x)) = g(x) = (∛(x+3))^3 -2 = x+3 -2
g(x) = x+1
Answer:
<u>A≈301.44</u>
Step-by-step explanation:
The area of a cylinder is A=2πrh+2πr^2
You first do the first problem of the equation (A=2πrh)
You fill in the radius and height ( A=2π(4)(8) )
You first multiply 4 x 8 = 32. ( A=2π(32) )
Then you multiply 2 x 32 = 64. ( A=π(64) )
Then you multiply π x 64 (using 3.14 for π) = 200.96 m^2
You then do the second part of the equation. (A=2πr^2)
You fill in the radius. (A=2π(4)^2)
Then multiply 4 x 4 = 16 (because it's to the power of 2 [4 times itself twice]) and then multiply it by 2.
16 x 2 = 32. ( A=π(32) )
Next you just multiply 32 x π (using 3.14 for π again) = 100.48 m^2.
Then you just add them together:
200.96 m^2 + 100.48 m^2 = 301.44 m^2
So <u>301.44 m^2</u> is your answer.
(I hopefully think it is.)
I need more information in order to solve it
Answer:
There is no solution to this answer.
Step-by-step explanation:
Leah's rate is 10x
Jason's rate is 20x
If you solve for 20x=10x, you get no solution. They are parallel lines.
Answer:
Step-by-step explanation:
Use consistent units. The length of the roller is 2.8 m. The diameter is 168 cm = 1.68 m
Circumference of roller = 1.68π m
Contact area of roller = 1.68π × 2.8 = 4.704π m²
Each rotation levels 4.704π m² of the playground.
Area of playground = 750 rotations × (4.704π m²)/rotation
= 3528π m²
≈ 11,084 m²
