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yawa3891 [41]
3 years ago
8

What symbol makes the sentence true? -3½ ? -3 5/9

Mathematics
1 answer:
kvasek [131]3 years ago
4 0

\frac{-63}{18}\geq \frac{-64}{18}

So, Option A is correct

Step-by-step explanation:

We need to identify the expression, that makes the sentence true:

-3\frac{1}{2}?-3\frac{5}{9}

First converting mixed fraction into improper fraction

-3\frac{1}{2}=\frac{-7}{2}

-3\frac{5}{9}=\frac{-32}{9}

For comparing both terms, their denominator should be same.

Multiplying \frac{-7}{2} by 9 and \frac{-32}{9} by 2 to make denominator same.

\frac{-7*9}{2*9}=\frac{-63}{18}

\frac{-32*2}{9*2}=\frac{-64}{18}

So, comparing terms \frac{-63}{18}\,\,and\,\,\frac{-64}{18}

\frac{-63}{18}? \frac{-64}{18}\\\frac{-63}{18}\geq \frac{-64}{18}

So, Option A is correct

Keywords: Comparing fractions

Learn more about Comparing fractions at:

  • brainly.com/question/7490805
  • brainly.com/question/4192226
  • brainly.com/question/1465430

#learnwithBrainly

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4 years ago
If f(x)=log10x, what is the approximate value of y in the equation 10^y=5?
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Molodets [167]

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Step-by-step explanation:

look at image for step by step

4 0
2 years ago
PLEASE HELP I HAVE AN HOUR LEFT!!
Yuki888 [10]

The statement that correctly describes the horizontal asymptote of g(x) is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the limit of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

g(x) = \frac{42x^3 - 15}{7x^3 - 4x^2 - 3}

The horizontal asymptote is given as follows:

y = \lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{42x^3 - 15}{7x^3 - 4x^2 - 3} = \lim_{x \rightarrow \infty} \frac{42x^3}{7x^3} = \lim_{x \rightarrow \infty} 6 = 6

Hence the correct statement is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

5 0
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