Question

Write the slope-intercept form of the equation that passes through the point (4,-6) and is parallel to the line y = -3/4x - 5 y = -3/4x - 3 y = -3/4x + 3 y = 4/3x + 2/3 y = 4/3x - 34/3

Answer 1

Answer:

$\large\boxed{y=-\dfrac{3}{4}x-3}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y = mx + b

m - slope

b - y-intercept

Parallel lines have the same slope.

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We have the equation of the line: $y=-\dfrac{3}{4}x-5$

The slope is $m=-\dfrac{3}{4}$.

Put the value of the slope and the coordinates of the point (4, -6) to an equation of a line:

$-6=-\dfrac{3}{4}(4)+b$

$-6=-3+b$           add 3 to both sides

$-3=b\to b=-3$

Finally:

$y=-\dfrac{3}{4}x-3$