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3 years ago

What is the square root of –16?

Mathematics

2 answers:

Effectus [21]3 years ago

8 0

The answer to your question will be 4 i

True [87]3 years ago

5 0

Answer:

$\boxed{\bold{4i}}$

Step By Step Explanation:

[ Step One ] Apply Radical Rule $\bold{\sqrt{-a}=\sqrt{-1}\sqrt{a}: \ \sqrt{-16}=\sqrt{-1}\sqrt{16}}$

$\bold{\sqrt{-1}\sqrt{16}}$

[ Step Two ] Apply Imaginary Number Rule: $\bold{\sqrt{-1}=i}$

$\bold{\sqrt{16}i}$

[ Step Three ] Simplify $\bold{\sqrt{16}}$

$\bold{\sqrt{16}: \ 4}$

[ Step Four ] Rewrite Equation

$\bold{4i}$

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The graph represents the x^2+y^2=8. Use the graph to answer questions 6,7,8.

finlep [7]

Answer:

6=69, 7=69, 8=69

Step-by-step explanation:

4 0

3 years ago

The sum of a number x and -7 is less than or equal to 18. Write and solve each inequality

vfiekz [6]

Answer:

x≤ 25.

Step-by-step explanation:

SO basically, the equation is x+-7≤ 18. What you do is you use the equation to solve for x. So, x+-7 is the same as x-7, so what you do is you add 7 from both sides to get x≤ 25.

Hope this helps:)

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4 years ago

Write an equation of the line that is parallel to y = 1/2x + 3 and passes through the point (10, -5).

bearhunter [10]

y = mx + b

"m" is the slope, "b" is the y-intercept (the y value when x = 0)

You need to find "m" and "b"

For lines to be parallel, the slopes have to be the same.

The given line's slope is 1/2, so the parallel line's slope is also 1/2.

y = 1/2x + b

To find "b", you can plug in the point (10, -5) into the equation.

y = 1/2x + b

-5 = 1/2(10) + b

-5 = 5 + b Subtract 5 on both sides to get "b" by itself

-10 = b

y = 1/2x - 10 Your answer is D (you could have just found the slope to get your answer, since all the slopes are different)

8 0

4 years ago

Find the equation of the line tangent to the graph of

garik1379 [7]

Answer:

$\displaystyle y=\frac{2\sqrt{3}}{15}x+\frac{\pi-2\sqrt{3}}{6}$

Step-by-step explanation:

We want to find the equation of the line tangent to the graph of:

$\displaystyle y=\sin^{-1}\big(\frac{x}{5}\big)\text{ at } x=\frac{5}{2}$

So, we will find the derivative of our equation first. Applying the chain rule, we acquire that:

$\displaystyle y^\prime=\frac{1}{\sqrt{1-(\frac{x}{5})^2}}\cdot\frac{1}{5}$

Simplify:

$\displaystyle y^\prime=\frac{1}{5\sqrt{1-\frac{x^2}{25}}}$

We can factor out the denominator within the square root:

$\displaystyle y^\prime =\frac{1}{5\sqrt{\frac{1}{25}\big(25-x^2)}}$

Simplify:

$\displaystyle y^\prime=\frac{1}{\sqrt{25-x^2}}$

So, we can find the slope of the tangent line at x = 5/2. By substitution:

$\displaystyle y^\prime=\frac{1}{\sqrt{25-(5/2)^2}}$

Evaluate:

$\displaystyle y^\prime=\frac{1}{\sqrt{75/4}}=\frac{1}{\frac{5\sqrt{3}}{2}}=\frac{2\sqrt{3}}{15}$

We will also need the point at x = 5/2. Using our original equation, we acquire that:

$\displaystyle y=\sin^{-1}(\frac{1}{2})=\frac{\pi}{6}$

So, a point is (5/2, π/6).

Finally, by using the point-slope form, we can write:

$\displaystyle y-\frac{\pi}{6}=\frac{2\sqrt{3}}{15}(x-\frac{5}{2})$

Distribute:

$\displaystyle y-\frac{\pi}{6}=\frac{2\sqrt{3}}{15}x+\frac{-\sqrt{3}}{3}$

Isolate. Hence, our equation is:

$\displaystyle y=\frac{2\sqrt{3}}{15}x+\frac{\pi-2\sqrt{3}}{6}$

7 0

3 years ago

Randy's parents gave him an allowance of d dollars each month. One month, he put half of his allowance in the bank and then boug

g100num [7]

Answer:

add 8 to the 12 and then multiply it by two

Step-by-step explanation:

8 + 12 = 20 * 2 = $40

7 0

3 years ago

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