Question

What are the possible lengths and widths of a rectangle if its length is 8 centimeters longer than the width, and the area is less than or equal to 33 square centimeters?

Answer 1

A = LW
A = (< = 33)
L = W + 8

W(W + 8) < = 33
W^2 + 8W < = 33
W^2 + 8W - 33 < = 0
(W + 11)(W - 3) < = 0

W + 11 < = 0
W < = -11 (extraneous solution)

W - 3 < = 0
W < = 3 <===

L < = W + 8
L < = 3 + 8
L < = 11 <===